Write a program that reads a positive odd whole number n and prints a pyramid wh

Question

Write a program that reads a positive odd whole number n and prints a pyramid where the first row contains all numbers from 1 to n (i.e., ascending order), the second row displays all numbers from 2 to n – 1, the third row displays all numbers from 3 to n – 2, etc. The last row will contain only a single value, i.e. the middle value in the range, i.e. 1 to n. Each successive row contains two fewer values than the previous row, i.e. the two values at the ends of the previous row are missing. For example, if n is 9, then the program will output:

123456789

2345678

34567

456

5

If n is 13, then the program will output:

1234567890123

23456789012

345678901

4567890

56789

678

7

The i’th row contains n – (2i – 2) values. Each column displays the same number. If a row has more than 10 digits, the digit after 9 should start again from 0.

Explanation / Answer

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int i,j,a=1,b,n,s;
cout<<"Enter lines : ";
cin>>n;

for(i=n; i>=1; i--)
{
s=n-i;
while(s!=0)
{
cout<<" ";
s--;
}
for(j=1; j<i*2; j++)
{
if(j<i)
{
cout<<a;
a++;
}
else if(j==i)
{
cout<<a;
b=a;
}
else
{
++b;
cout<<b;
a--;
}
}
a++;
cout<<" ";
}
getch();
}

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