Exercise 1 Find the error(s) in each of the following program segments. Write in

Question

Exercise 1 Find the error(s) in each of the following program segments. Write in a txt file the corrected commands a) printf ("The value is %d ", &number;); b) scanf("%d%d",&number1;, number2); c) printf ('Enter a value: d) int 3d; e) printf(%f, 123.879); Exercise 2 Write a program that prints the numbers 1 to 4 on the same line. Write the program using the following methods: a. Calling the function printf) once with four format specifiers. b. Calling the function printf) four times. Exercise 3 One mile equals 1609 meters. Write a program that a) Prompts the user to write his name and saves his name in a variable called name. eg.John b) Prompts the user to give a value of miles and saves the input in variable called miles. eg.1609 c) Converts the miles to kilometers. d) Prints the following message Hi John. The destination is 1 km

Explanation / Answer

Exercise 1

a) . Wrong statement:printf("The value is %d ",&number);

correct statement:printf("The value is %d ",number);

b. Wrong statement:scanf("%d%d",&number1,number2);

correct statement:scanf("%d%d",&number1,&number2);

c. Wrong statement:printf('enter a value');

correct statement:printf("enter a value");

d. Wrong statement:int 3d;

correct statement:int d;

e. Wrong statement:printf(%f,123.789);

correct statement:printf("%f",123.789);

Exercise 2:

a. printf("%d%d%d%d",1,2,3,4);

b. printf("1");

printf("2");

printf("3");

printf("4");

Exercise 3:

a. main() {

char name[20];

  

scanf("%s",name);

  

printf("%s",name);

}

b. int miles;

scanf("%d",&miles);

  

printf("%d",miles);

c. main()

{

  

float k,m;

printf("Enter miles");

scanf("%f",&m);

k=m*1.609;

printf("%f miles=%f kilometers",m,k);

}

d. printf("hi jhon");

printf("The destination is 1 km");

Exercise 4:

program determine the solutions of second order polynomial equation

#include <stdio.h>

#include <math.h>

main()

{

float a, b, c, determinant, x1,x2, real, imag;

printf("Enter coefficients a, b and c: ");

scanf("%f%f%f",&a,&b,&c);

determinant=b*b-4*a*c;

if (determinant>0)

{

x1= (-b+sqrt(determinant))/(2*a);

x2= (-b-sqrt(determinant))/(2*a);

printf("Roots are: %f %f",x1 , x2);

}

else if (determinant==0)

{

x1 = x2 = -b/(2*a);

printf("Roots are: %f %f", x1, x2);

}

else

{

real= -b/(2*a);

imag = sqrt(-determinant)/(2*a);

printf("Roots are: %f%f%f%f", real, imag, real, imag);

}

}

output of the program is:

Enter coefficients a, b and c:1 -5 6

Roots are: 3.000000

  

2.000000

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