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Hi, I am studying for a test and need some help deciphering the following Assemb

ID: 3671361 • Letter: H

Question

Hi, I am studying for a test and need some help deciphering the following Assembly Language code:

          mov     14, %o1

          subcc %o1, 4, %o0

          ble       else

          sub     %o0, 5, %o2

          call     .mul

          add    %o1, 5, %02

          ba      done

          clr      %o2

else: sub    %o0, 7, %o0

          call    .mul

          add   %o1, 9, %o2

done: nop

please include comments for each step through the code, explaining what each line does, and please also tell me what the final values of %o0, %o1, %o2

Thank you, I will thumb up all good answers

Explanation / Answer

   mov 14, %o1   !move 14 into %o1
2            subcc %o1, 4, %o0        !sub 4 from %o1 and store result in %o0
3           ble else        !branch if %o0 less than or equal to %o1
4           sub %o0, 5, %o2 !sub 5 from %o0
5           call .mul       ! multiply
6           add %o1, 5, %02 !add and store in %02
7           ba done        !branch to the label done
8           clr %o2       ! clear reg
9     else: sub %o0, 7, %o0    !
10          call    .mul
11          add   %o1, 9, %o2
12    done: nop

%o0=10
%o1=42
%o2=51
   

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