**Python** 1. Write a function called has_duplicates() that takes a list and ret
ID: 3669626 • Letter: #
Question
**Python**
1. Write a function called has_duplicates() that takes a list and returns True if any two items in the list are equal. So for example, has_duplicates([1,7,3,7,4]) should return True andhas_duplicates(["one","ONE","One"]) should return False.*
2. Write a function called remove_duplicates() that takes a list and removes any extra occurrences of values that appear multiple times in the list. I don't care what order the values in the new list have. So for example, if you have the definition L1 = ["a", "b", "a", "c", "c", "c"] and you run remove_duplicates(L1), then depending on how you implement this function, L1 could end up as ["a", "b", "c"], or as ["b", "a", "c"]. Either is acceptable.
Explanation / Answer
1)
import random
def has_duplicates(t):
sort = t[:]
sort.sort()
for i in range(len(sort)-1):
if sort[i] == sort[i+1]:
return True
def birthday_duplicates():
birthdays = []
count = 0
i = 0
while i < 1000:
for items in range(23):
birthdays.append(random.randint(1,365))
if has_duplicates(birthdays):
i +=1
return count/i * 100
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