Software Security The following table contains the partition table from the Mast
ID: 3665624 • Letter: S
Question
Software Security
The following table contains the partition table from the Master Boot Record for the volume in Figure 5.9, it is a list of sectors stored in different partitions. For each sector and partition, calculate the absolute address of the sector. (Hint: use a spreadsheet)
Table 5.5: Partition Table for the drive in Figure 5.9
(e.g.) Partition 0, sector 1
8 + 1 = 9
a. Partition 0, sector 8,184
b. Partition 1, sector 2,040
c. Partition 1, sector 10,000
d. Partition 2, sector 1
e. Partition 2, sector 4,088
Final Number Partition Sta nStarting Sector of Sectors ID Sector # 8 30,727 30.728 647 30,719 30,719 20,479 po 61,447 p2 61,448 61.448 81,927Explanation / Answer
There are three partitions are created i.e. P0, P1 and P2. Each Partition Startinng,Ending Sector (final Sector) and Total numbers of sectors are given in partition Table 5.5. and Size of Partion is specified in Figure 5.9 (in MB).
We can use the formula to find the address of required sector as
Starting sector of the partition + Sector numbers (whose address is required)
a. Partition 0, sector 8,184
Partition 0 start from Sector 8 and we have required to find the address of sector 8184 so the absolute address can be calculated as
8+8184 = 8192
b. Partition 1, sector 2,040
Partition 1 start from Sector 30728 and we have required to find the address of sector 2040 so the absolute address can be calculated as
30728 + 2040 = 32768
c. Partition 1, sector 10,000
Partition 1 start from Sector 30728 and we have required to find the address of sector 10000 so the absolute address can be calculated as
30728 + 10000 = 40728
d. Partition 2, sector 1
Partition 2 start from Sector 61448 and we have required to find the address of sector 1 so the absolute address can be calculated as
61448 + 1 = 61449
e. Partition 2, sector 4,088
Partition 2 start from Sector 61448 and we have required to find the address of sector 4088 so the absolute address can be calculated as
61448 + 4088 = 65536
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