Write a C++ class, Produce , that represents a type of produce for sale at a gro
ID: 3665402 • Letter: W
Question
Write a C++ class, Produce, that represents a type of produce for sale at a grocer, such as bananas or ground beef. Produce should have three member variables: a name (e.g. "white onions"), a unit price in units of dollars per pound (e.g. 0.79), and a Boolean representing whether the produce is perishable or not. Your class must include a constructor, and an accessor and update function for each data member.
Consider the following attempt to allocate a 10-element array of pointers to doubles and initialize the associate double values to 0.0. Rewrite the following (incorrect) code to do this correctly. (Hint: Storage for the doubles needs to be allocated.)
This question has 4 parts.
a) In general, when is it better to allocate an object statically on the stack (as opposed to dynamically on the heap)? Give an example of a programming scenario where an object should certainly be stack-allocated.
b) Now the opposite question: in general, when is it better to allocate an object dynamically on the heap (as opposed to the statically on the stack)? Give an example of a programming scenario where an object should certainly be heap-allocated.
c) In general, when is it better to use a reference over a pointer? Give an example of a programming scenario where it is certainly better to use a reference.
d) Now the opposite question: in general, when is it better to use a pointer over a reference? Give an example of a programming scenario where it is certainly better to use a pointer.
Explanation / Answer
a)
Stack allocation is much faster since all it really does is move the stack pointer. Using memory pools, you can get comparable performance out of heap allocation, but that comes with a slight added complexity and its own headaches.
Also, stack vs. heap is not only a performance consideration; it also tells you a lot about the expected lifetime of objects.
b)
Honestly, it's trivial to write a program to compare the performance:
It's said that a foolish consistency is the hobgoblin of little minds. Apparently optimizing compilers are the hobgoblins of many programmers' minds. This discussion used to be at the bottom of the answer, but people apparently can't be bothered to read that far, so I'm moving it up here to avoid getting questions that I've already answered.
An optimizing compiler may notice that this code does nothing, and may optimize it all away. It is the optimizer's job to do stuff like that, and fighting the optimizer is a fool's errand.
I would recommend compiling this code with optimization turned off because there is no good way to fool every optimizer currently in use or that will be in use in the future.
Anybody who turns the optimizer on and then complains about fighting it should be subject to public ridicule.
If I cared about nanosecond precision I wouldn't use std::clock(). If I wanted to publish the results as a doctoral thesis I would make a bigger deal about this, and I would probably compare GCC, Tendra/Ten15, LLVM, Watcom, Borland, Visual C++, Digital Mars, ICC and other compilers. As it is, heap allocation takes hundreds of times longer than stack allocation, and I don't see anything useful about investigating the question any further.
The optimizer has a mission to get rid of the code I'm testing. I don't see any reason to tell the optimizer to run and then try to fool the optimizer into not actually optimizing. But if I saw value in doing that, I would do one or more of the following:
Add a data member to empty, and access that data member in the loop; but if I only ever read from the data member the optimizer can do constant folding and remove the loop; if I only ever write to the data member, the optimizer may skip all but the very last iteration of the loop. Additionally, the question wasn't "stack allocation and data access vs. heap allocation and data access."
Declare e volatile, but volatile is often compiled incorrectly (PDF).
Take the address of e inside the loop (and maybe assign it to a variable that is declared extern and defined in another file). But even in this case, the compiler may notice that -- on the stack at least -- e will always be allocated at the same memory address, and then do constant folding like in (1) above. I get all iterations of the loop, but the object is never actually allocated.
Beyond the obvious, this test is flawed in that it measures both allocation and deallocation, and the original question didn't ask about deallocation. Of course variables allocated on the stack are automatically deallocated at the end of their scope, so not calling delete would (1) skew the numbers (stack deallocation is included in the numbers about stack allocation, so it's only fair to measure heap deallocation) and (2) cause a pretty bad memory leak, unless we keep a reference to the new pointer and call delete after we've got our time measurement.
On my machine, using g++ 3.4.4 on Windows, I get "0 clock ticks" for both stack and heap allocation for anything less than 100000 allocations, and even then I get "0 clock ticks" for stack allocation and "15 clock ticks" for heap allocation. When I measure 10,000,000 allocations, stack allocation takes 31 clock ticks and heap allocation takes 1562 clock ticks.
c)
There are two widely-used memory allocation techniques: automatic allocation and dynamic allocation. Commonly, there is a corresponding region of memory for each: the stack and the heap.
Stack
The stack always allocates memory in a sequential fashion. It can do so because it requires you to release the memory in the reverse order (First-In, Last-Out: FILO). This is the memory allocation technique for local variables in many programming languages. It is very, very fast because it requires minimal bookkeeping and the next address to allocate is implicit.
In C++, this is called automatic storage because the storage is claimed automatically at the end of scope. As soon as execution of current code block (delimited using {}) is completed, memory for all variables in that block is automatically collected. This is also the moment where destructors are invoked to clean up resources.
Heap
The heap allows for a more flexible memory allocation mode. Bookkeeping is more complex and allocation is slower. Because there is no implicit release point, you must release the memory manually, using delete or delete[] (free in C). However, the absence of an implicit release point is the key to the heap's flexibility.
Reasons to use dynamic allocation
Even if using the heap is slower and potentially leads to memory leaks or memory fragmentation, there are perfectly good use cases for dynamic allocation, as it's less limited.
Two key reasons to use dynamic allocation:
You don't know how much memory you need at compile time. For instance, when reading a text file into a string, you usually don't know what size the file has, so you can't decide how much memory to allocate until you run the program.
You want to allocate memory which will persist after leaving the current block. For instance, you may want to write a function string readfile(string path) that returns the contents of a file. In this case, even if the stack could hold the entire file contents, you could not return from a function and keep the allocated memory block.
Why dynamic allocation is often unnecessary
In C++ there's a neat construct called a destructor. This mechanism allows you to manage resources by aligning the lifetime of the resource with the lifetime of a variable. This technique is called RAII and is the distinguishing point of C++. It "wraps" resources into objects. std::string is a perfect example. This snippet:
actually allocates a variable amount of memory. The std::string object allocates memory using the heap and releases it in its destructor. In this case, you did not need to manually manage any resources and still got the benefits of dynamic memory allocation.
In particular, it implies that in this snippet:
there is unneeded dynamic memory allocation. The program requires more typing (!) and introduces the risk of forgetting to deallocate the memory. It does this with no apparent benefit.
Why you should use automatic storage as often as possible
Basically, the last paragraph sums it up. Using automatic storage as often as possible makes your programs:
d)
accepted
There are two widely-used memory allocation techniques: automatic allocation and dynamic allocation. Commonly, there is a corresponding region of memory for each: the stack and the heap.
Stack
The stack always allocates memory in a sequential fashion. It can do so because it requires you to release the memory in the reverse order (First-In, Last-Out: FILO). This is the memory allocation technique for local variables in many programming languages. It is very, very fast because it requires minimal bookkeeping and the next address to allocate is implicit.
In C++, this is called automatic storage because the storage is claimed automatically at the end of scope. As soon as execution of current code block (delimited using {}) is completed, memory for all variables in that block is automatically collected. This is also the moment where destructors are invoked to clean up resources.
Heap
The heap allows for a more flexible memory allocation mode. Bookkeeping is more complex and allocation is slower. Because there is no implicit release point, you must release the memory manually, using delete or delete[] (free in C). However, the absence of an implicit release point is the key to the heap's flexibility.
Honestly, it's trivial to write a program to compare the performance:
#include <ctime> #include <iostream> namespace { class empty { }; // even empty classes take up 1 byte of space, minimum } int main() { std::clock_t start = std::clock(); for (int i = 0; i < 100000; ++i) empty e; std::clock_t duration = std::clock() - start; std::cout << "stack allocation took " << duration << " clock ticks "; start = std::clock(); for (int i = 0; i < 100000; ++i) { empty* e = new empty; delete e; }; duration = std::clock() - start; std::cout << "heap allocation took " << duration << " clock ticks "; } It's said that a foolish consistency is the hobgoblin of little minds. Apparently optimizing compilers are the hobgoblins of many programmers' minds. This discussion used to be at the bottom of the answer, but people apparently can't be bothered to read that far, so I'm moving it up here to avoid getting questions that I've already answered.
An optimizing compiler may notice that this code does nothing, and may optimize it all away. It is the optimizer's job to do stuff like that, and fighting the optimizer is a fool's errand.
I would recommend compiling this code with optimization turned off because there is no good way to fool every optimizer currently in use or that will be in use in the future.
Anybody who turns the optimizer on and then complains about fighting it should be subject to public ridicule.
If I cared about nanosecond precision I wouldn't use std::clock(). If I wanted to publish the results as a doctoral thesis I would make a bigger deal about this, and I would probably compare GCC, Tendra/Ten15, LLVM, Watcom, Borland, Visual C++, Digital Mars, ICC and other compilers. As it is, heap allocation takes hundreds of times longer than stack allocation, and I don't see anything useful about investigating the question any further.
The optimizer has a mission to get rid of the code I'm testing. I don't see any reason to tell the optimizer to run and then try to fool the optimizer into not actually optimizing. But if I saw value in doing that, I would do one or more of the following:
-
Add a data member to empty, and access that data member in the loop; but if I only ever read from the data member the optimizer can do constant folding and remove the loop; if I only ever write to the data member, the optimizer may skip all but the very last iteration of the loop. Additionally, the question wasn't "stack allocation and data access vs. heap allocation and data access."
-
Declare e volatile, but volatile is often compiled incorrectly (PDF).
-
Take the address of e inside the loop (and maybe assign it to a variable that is declared extern and defined in another file). But even in this case, the compiler may notice that -- on the stack at least -- e will always be allocated at the same memory address, and then do constant folding like in (1) above. I get all iterations of the loop, but the object is never actually allocated.
Beyond the obvious, this test is flawed in that it measures both allocation and deallocation, and the original question didn't ask about deallocation. Of course variables allocated on the stack are automatically deallocated at the end of their scope, so not calling delete would (1) skew the numbers (stack deallocation is included in the numbers about stack allocation, so it's only fair to measure heap deallocation) and (2) cause a pretty bad memory leak, unless we keep a reference to the new pointer and call delete after we've got our time measurement.
On my machine, using g++ 3.4.4 on Windows, I get "0 clock ticks" for both stack and heap allocation for anything less than 100000 allocations, and even then I get "0 clock ticks" for stack allocation and "15 clock ticks" for heap allocation. When I measure 10,000,000 allocations, stack allocation takes 31 clock ticks and heap allocation takes 1562 clock ticks.
c)
There are two widely-used memory allocation techniques: automatic allocation and dynamic allocation. Commonly, there is a corresponding region of memory for each: the stack and the heap.
Stack
The stack always allocates memory in a sequential fashion. It can do so because it requires you to release the memory in the reverse order (First-In, Last-Out: FILO). This is the memory allocation technique for local variables in many programming languages. It is very, very fast because it requires minimal bookkeeping and the next address to allocate is implicit.
In C++, this is called automatic storage because the storage is claimed automatically at the end of scope. As soon as execution of current code block (delimited using {}) is completed, memory for all variables in that block is automatically collected. This is also the moment where destructors are invoked to clean up resources.
Heap
The heap allows for a more flexible memory allocation mode. Bookkeeping is more complex and allocation is slower. Because there is no implicit release point, you must release the memory manually, using delete or delete[] (free in C). However, the absence of an implicit release point is the key to the heap's flexibility.
Reasons to use dynamic allocation
Even if using the heap is slower and potentially leads to memory leaks or memory fragmentation, there are perfectly good use cases for dynamic allocation, as it's less limited.
Two key reasons to use dynamic allocation:
-
You don't know how much memory you need at compile time. For instance, when reading a text file into a string, you usually don't know what size the file has, so you can't decide how much memory to allocate until you run the program.
-
You want to allocate memory which will persist after leaving the current block. For instance, you may want to write a function string readfile(string path) that returns the contents of a file. In this case, even if the stack could hold the entire file contents, you could not return from a function and keep the allocated memory block.
Why dynamic allocation is often unnecessary
In C++ there's a neat construct called a destructor. This mechanism allows you to manage resources by aligning the lifetime of the resource with the lifetime of a variable. This technique is called RAII and is the distinguishing point of C++. It "wraps" resources into objects. std::string is a perfect example. This snippet:
int main ( int argc, char* argv[] ) { std::string program(argv[0]); } actually allocates a variable amount of memory. The std::string object allocates memory using the heap and releases it in its destructor. In this case, you did not need to manually manage any resources and still got the benefits of dynamic memory allocation.
In particular, it implies that in this snippet:
int main ( int argc, char* argv[] ) { std::string * program = new std::string(argv[0]); // Bad! delete program; } there is unneeded dynamic memory allocation. The program requires more typing (!) and introduces the risk of forgetting to deallocate the memory. It does this with no apparent benefit.
Why you should use automatic storage as often as possible
Basically, the last paragraph sums it up. Using automatic storage as often as possible makes your programs:
- faster to type;
- faster when run;
- less prone to memory/resource leaks.
d)
accepted
There are two widely-used memory allocation techniques: automatic allocation and dynamic allocation. Commonly, there is a corresponding region of memory for each: the stack and the heap.
Stack
The stack always allocates memory in a sequential fashion. It can do so because it requires you to release the memory in the reverse order (First-In, Last-Out: FILO). This is the memory allocation technique for local variables in many programming languages. It is very, very fast because it requires minimal bookkeeping and the next address to allocate is implicit.
In C++, this is called automatic storage because the storage is claimed automatically at the end of scope. As soon as execution of current code block (delimited using {}) is completed, memory for all variables in that block is automatically collected. This is also the moment where destructors are invoked to clean up resources.
Heap
The heap allows for a more flexible memory allocation mode. Bookkeeping is more complex and allocation is slower. Because there is no implicit release point, you must release the memory manually, using delete or delete[] (free in C). However, the absence of an implicit release point is the key to the heap's flexibility.
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