I have a program here that I thought I had worked all of the bugs out of, but I
ID: 3659978 • Letter: I
Question
I have a program here that I thought I had worked all of the bugs out of, but I am now getting an error. Could someone please help me solve what this error is. Thank You! Here is the error given and the program.
1>C:Program Files (x86)MSBuildMicrosoft.Cpp 4.0Microsoft.CppCommon.targets(562,5): error MSB6006: "mt.exe" exited with code -1073741818.
#include
<iostream>
#include
<fstream>
#include
<iomanip>
using
namespace std;
//prototype
int
getTreeNo();
int
getSpeciesCode(int[],string[]);
double
getDbh();
int
getTotHt();
double
calcTotVol(int,int[],double[],double[],double, int);
void
displayTreeData(ofstream&,int ,int ,int [], string [],double,int,double);
int
main(){
int
treeNo,speciesCode,totalHt,noTrees;
double
dbh;
double
totalVol,avgTotVol;
int
Species[6]={11,12,13,21,22,23};
string speciesDesc[6]={
"Loblolly Pine","White Pine","Red Pine","White Oak","Red Oak","Other Oak"};
double
b0[6]={1.2446,0.000,2.0822,.7316,1.6378,.7554};
double
b1[6]={.002165,.002364,.002046,.001951,.002032,.002174};
noTrees=0;
//set number of trees to 0
avgTotVol=0.0;
//set volume to 0
ofstream out(
"report.dat");//make a file out stream
out<<
"Forest Inventory Detail Edit and Volume Calculation "
<<
"Tree No. Species Description DBH Tot. Ht. Tot. Vol.";
cout<<setiosflags(ios::fixed)<<setprecision(3);
out<<setiosflags(ios::fixed)<<setprecision(3);
do
{
treeNo=getTreeNo();
if
(treeNo!=999){
speciesCode=getSpeciesCode(Species,speciesDesc);
dbh=getDbh();
totalHt=getTotHt();
totalVol=calcTotVol(speciesCode,Species,b0,b1, dbh, totalHt);
?
noTrees++;
//increment tree count
avgTotVol+=totalVol;
//add current tree's totalVol to avgTotVol
displayTreeData(out,speciesCode,treeNo,Species,speciesDesc,dbh,totalHt,totalVol);
}
}
while(treeNo!=999);
?
cout<<
" Total trees measured = "<<noTrees
<<
" Average total volume = ";
out<<
" Total trees measured = "<<noTrees
<<
" Average total volume = ";
if
(noTrees<=0){//if negative(which is impossible) or 0
cout<<0;
out<<0;
}
else
{
cout<<avgTotVol/noTrees;
out<<avgTotVol/noTrees;
}
cout<<
" Notes on Volume Determination Individual tree volumes are measured with different units. The formulas in this exercise are in cubic feet. Other common measurements are cords and cubic meters. Pulp wood is normally purchased by weight and saw logs by boardfeet. All of these can be converted from cubic feet. This exercise has taken several liberties as the real world is much more complicated than this.";
out<<
" Notes on Volume Determination Individual tree volumes are measured with different units. The formulas in this exercise are in cubic feet. Other common measurements are cords and cubic meters. Pulp wood is normally purchased by weight and saw logs by boardfeet. All of these can be converted from cubic feet. This exercise has taken several liberties as the real world is much more complicated than this.";
?
system(
"Pause");
return
0;
}
/*
getTreeNo
Input tree number, input must be type int and > 0 and less than 200 or = 999.
A value of 999 terminates input. Input is to be a do/while loop.
Function is return by value.
*/
int
getTreeNo(){
int
input;
do
{
cout<<
"Enter tree number(between 1-199) or 999 to finish: ";
cin>>input;
if
((input<1||input>199)&&input!=999){
cout<<
"Invalid number entered. ";
}
}
while((input<1||input>199)&&input!=999);
?
return
input;
}
/*
getSpeciesCode
Species code is type int and must be valid and found in the species table.
Input is a do/while loop. Function is return by value.
*/
int
getSpeciesCode(int Table[],string Name[]){
int
code;
int
found=0; //initialized to 0
do
{
//diplay Code & description
cout<<
" Code Description ";
for
(int i=0;i<6;i++){
cout<<Table[i]<<
" "<<Name<<endl;
}
//ask for input
cout<<
" Enter Species Code: ";
cin>>code;
//search Table to see if valid code entered
for
(int j=0;j<6;j++){
if
(code==Table[j]){//if found,
found =1;
//set found to 1
break
; //exit for loop
}
}
if
(found!=1){
cout<<
"Invalid code entered entered. ";
}
}
while(found!=1);
return
code;
}
/*
getDbh
Values are type double and must be greater than or equal to 5.0 and no greater than 50.6
inches. Is a return by value function.
*/
double
getDbh(){
double
inches;
do
{
cout<<
"Enter the number of inches(between 5 and 50.6): ";
cin>>inches;
if
(inches<5||inches>50.6){
cout<<
"Invalid number entered. ";
}
}
while(inches<5||inches>50.6);
return
inches;
}
/*
getTotHt
Values are type int and can range from 24 to 160.
Total height is always measured as the closest even integer.
For example, 131 would not be a valid measurement whereas 132 would be.
A return by value function.
*/
int
getTotHt(){
int
Ht;
do
{
cout<<
"Enter the closest even total height(between 24-160): ";
cin>>Ht;
if
((Ht<1||Ht>199)&&Ht%2!=0){
cout<<
"Invalid number entered Note that it must be a even number. ";
}
}
while((Ht<1||Ht>199)&&Ht%2!=0);
return
Ht;
}
/*
calcTotVol
Calculate total volume (type double)
totalVol = b0 + b1 (dbh)^2 ( totalHt)
Output is 3 decimal places to the right of the decimal.
Return by value function.
*/
double
calcTotVol(int code,int table[],double b0[],double b1[],double dbh, int totalHt){
int
index;
double
totalVol;
//find index
for
(int i=0;i<6;i++){
if
(code==table[i]){
index=i;
break
;
}
}
//calculate totalVol = b0 + b1 (dbh)^2 ( totalHt)
totalVol=b0[index]+b1[index]*dbh*dbh*totalHt;
return
totalVol;
}
/*
*/
void
displayTreeData(ofstream& out,int speciesCode,int treeNo,int table[], string Name[],double dbh,int totalHt,double totalVol){
int
index;
//find index
for
(int i=0;i<6;i++){
if
(speciesCode==table[i]){
index=i;
break
;
}
}
cout<<
" Tree No. Species Description DBH Tot. Ht. Tot. Vol.";
cout<<endl<<treeNo<<
" "<<Name<<" "<<setprecision(1)<<dbh<<" "<<totalHt<<" "<<setprecision(3)<<totalVol<<endl;
out<<endl<<treeNo<<
" "<<Name<<" "<<setprecision(1)<<dbh<<" "<<totalHt<<" "<<setprecision(3)<<totalVol;
?
system(
"Pause");
return
;
}
?
Explanation / Answer
you are still missing the string library. add the header #includeRelated Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.