A computer system has a word addressable memory. Each word is 32 bits (4 bytes)

Question

A computer system has a word addressable memory. Each word is 32 bits (4 bytes) wide. There are 24 memory address lines. What is the maximum available system memory? 64k bytes 64M bytes 4G bytes 16M bytes 256M bytes 16G bytes How many data lines are required for the system in the previous question? 8 24 28 16 26 32 If the system in the previous questions were instead byte-addressable, and were to retain the same total number of bytes of memory, how many address lines would it require? 8 24 28 16 26 32 Given a very peculiar memory system that uses 22 bit-addressing, and is "three-bit" addressable (i.e. each location in memory stores 3 bits), how many bits of storage does the memory contain in total? 88 bits 1 Mbits 16 Mbits 64kbits 12 Mbits 64 Mbits

Explanation / Answer

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