Prove by induction n2 > 5n + 10 for n > 6. (Hint #1, use the weak principle of m

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n^2 > 5n+10 for n>6 we have to check weather it is true for n = starting number, then we shud assume that it is true for n = n and prove it true for n = n+! for n = 7 49 > 45 it is true let it is true for n so n^2 > 5n+10 we have to prove that (n+1)^2 > 5(n+1) + 10 n^2 + 2n + 1 > 5n + 10 +5 as 2n + 1 is always > 5 for all n > 2 and n^2 > 5n+10 so n^2 + 2n + 1 > 5n + 10 +5 hence proved that n^2 > 5n+10 for n>6

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