Given the following structure and variable definitions, struct customer { char l

Question

Given the following structure and variable definitions,

struct customer {

char lastName[ 15 ];

char firstName[ 15 ];

unsigned int customerNumber;

struct {

char phoneNumber[ 11 ];

char address[ 50 ];

char city[ 15 ];

char state[ 3 ];

char zipCode[ 6 ];

} personal;

} customerRecord, * customerPtr;

customerPtr = & customerRecord;

Write an expression that can be used to access the structure members in each of the following parts:

a) Member lastName of structure customerRecord.

CostumerRecord.lastName

b) Member lastName of the structure pointed to by customerPtr.

customerPtr->lastName or (*customerPtr).lastName

c) Member firstName of structure customerRecord.

customerRecord.firstName

d) Member firstName of the structure pointed to by customerPtr.

customerPtr->firstName or (*customerPtr).firstName

e) Member customerNumber of structure customerRecord.

customerRecord.customerNumber

f) Member customerNumber of the structure pointed to by customerPtr.

customerPtr->customerNumber or (*customerPtr).customerNumber

g) Member phoneNumber of member personal of structure customerRecord.

customerRecord.personal.phoneNumber

h) Member phoneNumber of member personal of the structure pointed to by customerPtr.

customerPtr->personal.phoneNumber or (*customerPtr).personal.phoneNumber

i) Member address of member personal of structure customerRecord.

j) Member address of member personal of the structure pointed to by customerPtr.

k) Member city of member personal of structure customerRecord.

l) Member city of member personal of the structure pointed to by customerPtr.

m) Member state of member personal of structure customerRecord.

n) Member state of member personal of the structure pointed to by customerPtr.

o) Member zipCode of member personal of structure customerRecord.

p) Member zipCode of member personal of the structure pointed to by customerPtr.

Explanation / Answer

a) customerRecord.lastname[] b)&customerPtr.lastname[] c)customerRecord.firstname[] d)&customerPtr.firstname[] e)customer.customerNumber f)&customerPtr.customerNumber g)customerRecord.personal.phoneNumber[] h)&customerPtr.personal.phoneNumber[] I) j) k l m n o and p are in the same way. Just replaceNumber by respective data

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