Step 4: Execute the following version of the program from Step 1 and explain the

Question

Step 4: Execute the following version of the program from Step 1 and explain the results.

#include <iostream>
using namespace std;

char x;

void fun3();
void fun4();

int main()
{
x = 'Z';
cout << " x = " << x << endl;
fun3();
cout << "x = " x << endl;
fun4();
cout << "x = " << x << endl;

return (0);
}

void fun3() {
x = 'H';
cout << x << "ey Dickinson is in North Dakota not Texas! ";
}

void fun4()
{
x = 'Y';
cout << x << "ou bet it's cold! ";
}

Explanation / Answer

Output: x =Z Hey Dickinson is in North Dakota not Texas! x =Z You bet it's cold! x =Z Explanation: x whenever printed in the main code will always execute x = Z because its scope is limited to the main code only. X defined in fun3() and fun4() when executed will print the local variable X whatever the value has been initialised in the respective function.

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