this is from introduction to java 8th ed by Liang chapter 13 problem PE 7 exerci

Question

this is from introduction to java 8th ed by Liang chapter 13 problem PE 7
exercise 9.8 specifies the binaryToDecimal-(String binaryString) method which converts a binary string into a decimal number.implement the binaryToDecimal method to throw a numberFormatException if the string is not a binary string.

exercise 9.8
import java.util.Scanner;
public class Exercise09_08 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a binary number string: ");
String str = input.nextLine();
int B2D = binaryToDecimal(str);
System.out.println("The decimal value is " + B2D);
}
public static int binaryToDecimal(String binaryString) {
int decimalValue = 0;
for (int i = 0; i < binaryString.length(); i++) {
Character binary = binaryString.charAt(i);
String temp = binary.toString();
int tempInt = Integer.parseInt(temp);
decimalValue = decimalValue * 2 + tempInt;
}
return decimalValue;
}
}

Explanation / Answer

import java.util.Scanner;
import java.util.regex.Pattern;
public class Exercise09_08
{
    public static void main(String[] args)
    {
        Scanner input = new Scanner(System.in);
        System.out.print("Enter a binary number string: ");
        String str = input.nextLine();
        try
        {
         int B2D = binaryToDecimal(str);
         System.out.println("The decimal value is " + B2D);
        }
        catch(NumberFormatException exp)
        {
            System.out.println("Input string is not in a binary format.");
        }
      
    }
  
    public static int binaryToDecimal(String binaryString)
    {
        String pattern = "[0-1]*";
        boolean patternMatched = Pattern.matches(pattern, binaryString);  
        if(patternMatched)
        {
            int decimalValue = 0;
            for (int i = 0; i < binaryString.length(); i++)
            {
                Character binary = binaryString.charAt(i);
                String temp = binary.toString();
                int tempInt = Integer.parseInt(temp);
                decimalValue = decimalValue * 2 + tempInt;
            }
            return decimalValue;
        }
        else
        {
            throw new NumberFormatException("Given string is not in binary format.");
        }
    }
}

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