Please comment all steps as I\'m new to programming and need the influence. This

Question

Please comment all steps as I'm new to programming and need the influence. This program has to be written in C and be able to be compiled on emacs. Thank you

Write a program weekday.c that prompts the user for a date (entered as month/day) this year, and outputs the day of the week the date falls on. Use the fact that this year (2011), January 1st was a Saturday and that January, March, May, July, August, October, and December have 31 days, April, June, September, and November have 30 days, and February this year had 28 days. Note: Do not specify in the program the rst day of each month (e.g., that February 1st will fall on a Tuesday, etc.). Instead, use one switch statement to calculate the number of days till the date
entered, and another switch statement to print the day of the week.
Here is a sample run:
(~)$ a.out
Enter today's date: 03/21
Happy Monday!
(~)$ a.out
Enter today's date: 5/14
Happy Saturday!
(~)$ a.out
Enter today's date: 11/24
Happy Thursday!
(~)$


This is what I have come up with so far. I'm not sure how to link thw switch to everything??

// program to return the day of the week given the date (jan 1st Sat.)
#include <stdio.h>

int main()
{


int value1 = month, value2 = day
int date = month/day
int year = 365
int month = 12



for(jan1sat = 1, month =>1 && month =<12 || day =>1 && day =<31, ++jan1sat)
{

printf("Enter today's date: ");
scanf("%d/%d, &jan1sat);

switch(date)
{


case 7:
printf("Happy Sunday! ");

break;
case 6:
printf("Happy Monday! ");

break;
case 5:
printf("Happy Tuesday! ");

break;
case 4:
printf("Happy Wednesday! ");

break;
case 3:
printf("Happy Thursday! ")

break;
case 2:
printf("Happy Friday! ")

break;
case 1:
printf("Happy Saturday! ");

break;


return 0;
}
}

}

Explanation / Answer

please rate - thanks

// program to return the day of the week given the date (jan 1st Sat.)
#include <stdio.h>

int main()
{char input[6];
int i,month=0,day=0;
printf("Enter today's date:(m/d) ");
scanf("%s", &input);
for(i=0;input[i]!='/';i++)
     month=month*10+(input[i]-'0');
i++;
for(;input[i]!='';i++)
     day=day*10+(input[i]-'0');
day--;
for(i=1;i<month;i++)
   {switch(i)
    {case 1:
    case 3:
    case 5:
    case 7:
    case 8:
    case 10:
    case 12:   day+=31;
               break;
    case 2:    day+=28;
               break;
    default:   day+=30;
               break;
     }
}
day%=7;
switch(day)
{
case 1:
printf("Happy Sunday! ");
break;
case 2:
printf("Happy Monday! ");
break;
case 3:
printf("Happy Tuesday! ");
break;
case 4:
printf("Happy Wednesday! ");
break;
case 5:
printf("Happy Thursday! ");
break;
case 6:
printf("Happy Friday! ");

break;
case 0:
printf("Happy Saturday! ");
break;
}
getch();
return 0;
}

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