This is a code file that creates a Christmas tree pattern. I am writing the code

Question

This is a code file that creates a Christmas tree pattern. I am writing the code in Visual Studio 2008 Express. I am getting the correct tree pattern based on the number of lines the user inputs (between 1 and 30). However, I still need to display the line number for each line of the tree in the DOS window. I have experiented using setw(), but then the output tree pattern would look crazy. I am wondering how I can display the line number for each line of the tree without messing up the tree.

#include
#include

using namespace std;

int main()
{

int i,j,s;
int lines;
char response = 'Y';

do//Begin outer loop.

{
do//Loop to get correct input.
{
cout << "Enter number of lines for tree (between 1 and 30): ";
cin >> lines;

}while(lines < 1 || lines > 30);
cout << endl << endl;

for (i = 1; i <= lines; i++)

{
for (j = 1; j <= lines - i; j++)
{
cout << " ";
}

for (s = 1; s <= (i * 2) - 1; s++)
{
cout << "*";


}

cout << endl;
}
cout << " Keep going?: ";//can create multiple trees.
cin >> response;
}while (response == 'Y' || response == 'y');//End outer loop.

return 0;
}

Explanation / Answer

#include <iomanip>
#include <iostream>

using namespace std;

int main()
{

int i,j,s;
int lines;
char response = 'Y';

do//Begin outer loop.

{
do//Loop to get correct input.
{
cout << "Enter number of lines for tree (between 1 and 30): ";
cin >> lines;

}while(lines < 1 || lines > 30);
cout << endl << endl;

for (i = 1; i <= lines; i++)

{
cout << i <<" ";
for (j = 1; j <= lines - i; j++)
{
cout << " ";
}

for (s = 1; s <= (i * 2) - 1; s++)
{
cout << "*";


}

cout << endl;
}
cout << " Keep going?: ";//can create multiple trees.
cin >> response;
}while (response == 'Y' || response == 'y');//End outer loop.

return 0;
}

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