Write a C program that displays all numbers that satisfy this equations x*y* z =

Question

Write a C program that displays all numbers that satisfy this equations x*y* z = x^3 + y^3 + z^3, x < N, y < N, and z < N.

SO , what I understand from this question is that I need to make the tow sides of the equation are equal and that happen only when x=y=z= 0 , so I will use for loop and put the value of x , y , z equal to zero and then the program must ask me to insert the value of n . Then the progam must chack if the value of n bigger or simaller than x , y and z . if it is simller , the program must print out xyz . I try to do it in this way , but I can not make the program run , so does anyone have idea how to do it ?

Explanation / Answer

please rate - thanks

#include <stdio.h>
#include <conio.h>
int main()
{int x,y,z,N;
printf("enter a value for N: ");
scanf("%d",&N);
printf("x*y* z = x^3 + y^3 + z^3, x < N, y < N, and z < N when ");
for(x=0;x<N;x++)
      for(y=0;y<N;y++)
            for(z=0;z<N;z++)
                 if(x*y*z==x*x*x+y*y*y+z*z*z)
                     printf("x=%d, y=%d, z=%d ",x,y,z);
getch();
return 0;
}

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