A. Write a function that takes an array of ints, and the size of the array – ano

Question

A.     Write a function that takes an array of ints, and the size of the array – another int. It returns a double. Call this one ‘averageArray.’ Return a double that is the average of the values in the array. Demonstrate that it works by finding the average of an array with these values {78, 90, 56, 99, 88, 68, 92}

The code below didn't work

#include <stdio.h>
#include <stdlib.h>

double averageArray(int a[7], int len){
    int i,sum;
    for(int i=0;i<len;i++){
    sum=sum+a[i];
    }
    return((double)sum/len);
}
main(){

    int i;
    int per[20];
    for(i=0; i<7; i++){
    printf("enter the numbers");
    scanf("%d", &per[i]);}
    printf("avg: %f",averageArray( per,7));

    system("pause");
}

Explanation / Answer

please rate - thanks

I cleaned it up a bit, the only real problem was to change int i=0 to i=0 in the function

#include <stdio.h>
#include <stdlib.h>

double averageArray(int a[], int len){
    int i,sum;
    for(i=0;i<len;i++){
    sum=sum+a[i];
    }
    return((double)sum/len);
}
main(){

    int i,n;
    int per[20];
    printf("How many numbers do you have? ");
    scanf("%d",&n);
    for(i=0; i<n; i++){
    printf("enter number %d: ",i+1);
    scanf("%d", &per[i]);}
    printf("avg: %.3f ",averageArray( per,n));

    system("pause");
}

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