Question 1 Not yet answered Marked out of 50.00 SAMPLE 79.2 78.8 80.0 78.4 81.0
ID: 362320 • Letter: Q
Question
Question 1 Not yet answered Marked out of 50.00 SAMPLE 79.2 78.8 80.0 78.4 81.0 80.5 78.7 81.0 80.4 80.1 79.6 79.6 80.4 80.3 80.8 78.9 79.4 79.7 79.4 80.6 80.5 79.6 80.4 80.8 78.8 79.7 80.6 80.5 80.0 81.1 Flag question Computer upgrades have a nominal time of 80 minutes. Samples of five observations each have been taken, and the results are as listed. Using factors from Table 10.3 Determine the upper limits for the mean chart first. Round to two-decimal places. Answer Question 2 Not yet answered Marked out of 50.00 determine the upper control limit of range chart. Round to two-decimal places. Answer: Flag questionExplanation / Answer
Mean (x bar)= sum of all values/number of observations. The number of observations = 5.
R = highest - lowest
Now, x double bar = average of all means = 79.48+80.14+79.6+80.02+80.38/6 = 79.96
R bar = average of all R's = 2.6+2.3+1.2+1.7+2+1.4 = 1.87
Mean chart: UCL = X double bar+A2*R bar. A2 = 0.58 (as n = 5) and LCL = X double bar-A2*R bar
UCL = 79.96+0.58*1.87 = 81.04
LCL = 79.96 - 0.58*1.87 = 78.88
Range chart:
UCL = D4*R bar. D4 = 2.11 (as n = 5). Thus UCL = 2.11*1.87 = 3.95
LCL = D3*R bar. D3 = 0 (as n = 5). Thus LCL = 0*1.87 = 0.
Answer to Q1) UCL of Mean Chart is 81.04
Answer to Q2) UCL of Range Chart is 3.95
1 2 3 4 5 6 79.2 80.5 79.6 78.9 80.5 79.7 78.8 78.7 79.6 79.4 79.6 80.6 80.0 81.0 80.4 79.7 80.4 80.5 78.4 80.4 80.3 79.4 80.8 80.0 81.0 80.1 80.8 80.6 78.8 81.1 Mean 79.48 80.14 80.14 79.60 80.02 80.38 Range 2.60 2.30 1.20 1.70 2.00 1.40Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.