The following program works but it needs to be modified toread an int rather tha

Question

The following program works but it needs to be modified toread an int rather than a double. (Note that sqrt () isnot defined for an int so assign n to a double and take sqrt() ofthat).

#include <iostream>
#include <cmath>
using namespace std;
int main ()
{
cout<< "Please enter a floating-point value :";
double n ;
cin >> n ;
cout << " n == "<< n
<<" n+1 == " << n+1
<< " three times n == " << 3 * n
<< " twice n == "<< n + n
<< " n squared == "<< n * n
<< " half of n == " << n/2
<<" square root of n ==" <<sqrt(n)
<<endl ; // another name for newline ("end of line")
return 0;
}

Explanation / Answer

//Hope this will help you, //You should typecast before you pass tosqrt. #include #include using namespace std; int main () { cout> n ; cout

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