Write arecursive function that takes three arguments (an integer array,starting

Question

Write arecursive function that takes three arguments (an integer array,starting subscript ‘s’ and

endingsubscript ‘e’ ).

In firstrecursive call, the function should display the array fromsubscript ‘s’ (s = 0) to ‘e’ (e=

size ofarray). In each successive call, the function should print thearray from index s+1 to e. The

functionshould stop processing and return when starting subscript becomesequal to ending

subscript.

For example,if user enters values for array 2, 3, 4, 5, 6 then the recursivefunction must display

the followingoutput.

2 3 4 56

3 4 56

4 56

56

6

Explanation / Answer

#include<iostream.h> #include<conio.h> void recursive(int [],int,int); void main() {    int array[5];    for(int i=0;i<5;i++)    {    cout<<" Enter the"<<i<<" Index number :";    cin>>array[i];    }    recursive(array,0,4); //0 is thestarting index and 4 is the ending subscript    getche(); } void recursive(int arr[],int s,int e) {    if(s!=e+1)    {    for(inti=s;i<=e;i++)      cout<<arr[i]<<" ";;
   cout<<endl;    s++;    recursive(arr,s,e);    //Recursivecall    } }      

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