In a tictactoe game, I need to search the rows and colums of a2D arrray (the gam

Question

In a tictactoe game, I need to search the rows and colums of a2D arrray (the game board) for the winner. This is what I have, butI know there is a shorter way. Can someone help me find the easierway to do this? Thank you.   if ((board[0][0] =='X') && (board [1][0] == 'X') && (board[2][0] =='X'))
  {
   System.out.println("X is the winner!congratulations!");
   theWinner = true;
  }   else if((board [0][0] =='O') && (board [1][0] =='O') &&(board [2][0] =='O'))
  {
   System.out.println("O is the winner!Congratulations!");
   theWinner = true;
  } In a tictactoe game, I need to search the rows and colums of a2D arrray (the game board) for the winner. This is what I have, butI know there is a shorter way. Can someone help me find the easierway to do this? Thank you.   if ((board[0][0] =='X') && (board [1][0] == 'X') && (board[2][0] =='X'))
  {
   System.out.println("X is the winner!congratulations!");
   theWinner = true;
  }   else if((board [0][0] =='O') && (board [1][0] =='O') &&(board [2][0] =='O'))
  {
   System.out.println("O is the winner!Congratulations!");
   theWinner = true;
  }

Explanation / Answer

for(int r = 0; r < 3;r++) {    char temp =board[r][0];    if(temp != 'O'&& temp != 'X')    {       continue;    }    theWinner =true;        for(int c = 1; c< 3; r++)    {       if(board[r][c] !=temp)       {          theWinner= false;          break;       }    }    if(theWinner)    {       // a player haswon    } }

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