Leap year. Write a function bool leap_year(int year); that tests whether a year

Question

Leap year. Write a function

bool leap_year(int year);

that tests whether a year is a leap year: that is, a year with 366days. Leap years are necessary to keep the calendar synchronizedwith the sun because the earth revolves around the sun once every365.25 days. Actually, the figure is not entirely precise, and forall dates after 1580 the Gregorian correction applies. Usuallyyears that are divisible by 4 but is not a century year are leapyears, century years that are not divisible by 400 are not leapyears, century years that are divisible by 400 are leap years.

Write a program to test your leap_year() function with at least oneinput year from each of the following four year types.

1. Non-century non-leap years (e.g., 1995, 1997)
2. Non-century leap years (e.g, 1980, 1984)
3. Century non-leap years (e.g., 1700, 1800)
4. Century leap years (e.g., 2000, 2400)

Explanation / Answer

Can't give you the C++ code but I can give you the algorithm. " If year%400 == 0        leapyear = True elif year%100 == 0        leapyear = False elif year%4 == 0        leapyear = True else        leapyear = False " where % means the remainder of the division (i.e 7%3 = 1)

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