i need help translating this code into c language. PROGRAM IMPLICIT NONE INTEGER

Question

i need help translating this code into c language.

PROGRAM
IMPLICIT NONE

INTEGER::divx,i
REAL(kind=8)::approx,approx1,delx,x,count

delx=0
divx=0
approx=0
count=0

DO
count=count+1
divx=divx*2
delx/1./divx

x=0
approx1=0
          DOi=1,divx
               delx=1./divx
               x=x+delx
               approx1=approx1+delx*sqrt(1-x**2)
           ENDDO
IF (abs(approx1-approx)<.00000001)EXIT
approx=approx1
END DO
WRITE(*,*)'pi=',approx*4
WRITE(*,*)'number of iterations:',count

END PROGRAM


pretty simple program but i dont know how to write in thec-language yet. please help

Explanation / Answer

please rate - thanks I changed count to integer instead of double, I started divx at 1 instead of 0 FORTRAN is really much better for this #include #include #include #include int main() {int divx,i,count; double approx,approx1,delx,x; delx=0; divx=1; approx=0; approx1=0; count=0; do {approx=approx1;    count++;    divx*=2;    delx=1./divx;    x=0;    approx1=0;    for(i=1;i.00000001); printf("pi = %lf ",approx1*4); printf("number of iterations: %d ",count); getch(); return 0; }

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