Write a C program to display the binary, octal, and hexadecimalconversions of an

Question

Write a C program to display the binary, octal, and hexadecimalconversions of an integer expression. for input accepteight-character strings whose first character is +, -, or a digitand whose remaining characters are all digits. Whenconverting from base 10 to another base, do not use any arithmeticoperators (+, -, *, /) and also do not use binary, octal, or hexconversion sequences to display the conversions. Allow theuser to enter an expression either interactively or on the commandline. Must be written in c and able to run on the gcccompiler

Explanation / Answer

please rate - thanks does this work? #include #include int main() {char hex[6]={'A','B','C','D','E','F'}; int numbits,num,digits,shifted,i,j; numbits=sizeof(int)*8;   //get number of bitsconverting printf("Enter integer you want to convert (0 when done): "); scanf("%d",&num); while(num!=0)    {printf("hex: ");      for(i=28;i>=0;i-=4)       {shifted=num;          //don't destroy original number        shifted=shifted>>i;    //shift to theright        shifted=shifted&15;    //use mask to get 4 rightmost bits;         if(shifted=0;i--)       {shifted=num;          //don't destroy original number        shifted=shifted>>i;    //shift to theright        shifted=shifted&1;    //use mask to get rightmost bit        printf("%d",shifted);     //print the digit         }      printf(" ");                  //when done with all digits go to next line      printf("octal: ");      for(i=30;i>=0;i-=3)       {shifted=num;          //don't destroy original number        shifted=shifted>>i;    //shift to theright         if(i==30)           shifted=shifted&3;         else        shifted=shifted&7;    //use mask to get rightmost bit        printf("%d",shifted);     //print the digit         }       printf(" ");        //whendone with all digits skip 2 lines     printf("Enter integer you want to convert (0when done): ");    scanf("%d",&num);               } getch(); return 0; }

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