Rules for Calculating Time Complexity andBig-Oh Rule 00 Normally these formulas
ID: 3609895 • Letter: R
Question
Rules for Calculating Time Complexity andBig-Oh
Rule 00
Normally these formulas are very handy:
If then
Also,
Rule 0
The condition that stops a loop executes ONE MORE time than theloop itself (the last time is when it is evaluated false)
Rule 1
for (i=0;i<n;i=i+k) Anything inside theloop will run approximately n/k times
Rule 2
for (i=n;i>0;i=i-k) Anything inside the loop will run approximatelyn/k times
Rule 3
for (i=1;i<n;i=i*k) Anything inside theloop will run approximately logkntimes
Rule 4
for(i=1;i<=n;++i)
for (j=1;j<=i;++j)
The above nested loop approximately runs ½n(n+1) times.
The variable j depends upon the value of i
Rule 5
for(i=1;i<=n;i=i*2)
for (j=1;j<=i;++j)
The statements in the above nested loop approximately run2n-1 times.
The variable j depends upon the value of i
Rule 6
If the loop variables are independent then the total times astatement inside a nested loop is executed is equal to the productof the times the individual loops run
e.g. for (i=0;i<n;++i)
for (j=0;j<m;++j)
A statement inside the above nested loop will runn*m times
Question # 1
[Marks: 10]
Find the running time complexity of the following pieceof code and show your working step by step.
x=0;
for (i=1;i<=n;i=i*2)
{ for(j=1;j<=2n;++j)
{
x=x+1;
}
}
Question # 2
[Marks: 10]
Write the algorithm for Quick sort and calculate time T(n) for each step of the algorithm.
Explanation / Answer
[Marks: 10]
Find the running time complexity of the following pieceof code and show your working step by step.
x=0;
for(i=1;i<=n;i=i*2) it will go lg2n
{ for(j=1;j<=2n;++j) it will go 2n times
{
x=x+1; //it will go 2nlg2n
}
}
so complexity will be O(n lg2n)
Question # 2
[Marks: 10]
Write the algorithm for Quick sort and calculate time T(n) for each step of the algorithm.
worst caseanalysis.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.