Your job for this assignment is to create a simple program thatdetermines if a s

Question

Your job for this assignment is to create a simple program thatdetermines if a string is an email address. Roughly speaking, anemail address is a string that contains exactly one occurrence ofthe symbol "@", does not start with a ".", and has certain otherrestrictions on the kinds of symbols allowed. For a fairly completeaccount of those restrictions, read: http://en.wikipedia.org/wiki/E-mail_address. To simply mattershowever, we'll assume our own slightly simplified rules: a stringis a legal email address if:

* it does not begin with a "." or an "@";
* has exactly one occurence of @;
* it is made up only of numbers, letters, dots, or @.


Your job for this assignment is to write a single class applicationcalled EMail (file name:EMail.java),
which reads in a single string from the keyboard; if the string isa legal address according to this definition, your program shouldprint
Legal email address? true
if the string isn't legal, your program should print
Legal email address? false

Some tips:

1) You may want to use a (static) method in the Character classcalled isLetterOrDigit, which returns boolean. Thus

Character.isLetterOrDigit('a')

returns true, but

Character.isLetterOrDigit('@')

returns false.



This is what i have so far, and somehow whenever i entered an emaillike "bebe@yahoo.com" it gives me "it is valid" and "it isinvalid". Can someone help me how to fix this problem? thanks.
import java.util.Scanner;

public class Email {

public static void main(String[] args) {
    System.out.println("Enter the email: ");
    Scanner scan = new Scanner(System.in);
    String email = scan.nextLine();
    System.out.println(email);
    int count = 0;
for( int i = 0; i<email.length(); i++){
      char letter = email.charAt(i);
      if(letter == '@'){
      {
        count ++;
        }
      if(email.charAt(0) =='@' ||email.charAt(0) == '.' ||count !=1)
      System.out.println("It isInvalid");
      //else if(count !=1)
      // System.out.println("invalid");
    else
      System.out.println("It isValid");
   
    }
    }
}
}

Explanation / Answer

Dear User, below is the code that does what you need. The code might notcompile due to case errors as i do not have a java compiler handyat the moment. Please let me know if the comments are unclear or if you need moreclarification. public static void main(String[] args) {     Systemout.println("enter the email: ");     Scanner scan = new Scanner(System.in);     String email.scan.nextLine();     System.out.println(email);     System.out.println("Valid email? " +ValidateEmail(email)); } private void bool validateEmail(String email) {     int count=0; //flag for number of '@'     //if it start with @ or . stop checking andreturn false     if(email.charAt90).Equals('@') ||email.charAt90).Equals('.'))     {         return False;     }     for (int i=0; i0) then return false there is two @in there             if(count>0)             {                return false;             }            count++;         }         //if character is not letteror digit and it is not a '.' then return false invalid email         //Must check for '.' since wealready checked it is not the start        if(!(Character.isLetterOrDigit(part) &&part.equals('.')))         {             returnfalse;         }     }     //reached the end everythign is valid     return true; }

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