Given the following: public void myst(int n) { if(n <= 0) System.out.print(\"*\"

Question

Given the following: public void myst(int n)
{    if(n <= 0)    System.out.print("*");    else if(n % 2 == 0)    {    System.out.print("(");    myst(n - 1);    System.out.print(")");    }    else    {    System.out.print("[");    myst(n - 1);    System.out.print("]");    } } What is printed by the method call: a) myst(0)___________ b) myst(1)___________ c) myst(2)___________ d) myst(3)___________ e) myst(6)___________ Given the following: public void myst(int n)
{    if(n <= 0)    System.out.print("*");    else if(n % 2 == 0)    {    System.out.print("(");    myst(n - 1);    System.out.print(")");    }    else    {    System.out.print("[");    myst(n - 1);    System.out.print("]");    } } What is printed by the method call: a) myst(0)___________ b) myst(1)___________ c) myst(2)___________ d) myst(3)___________ e) myst(6)___________

Explanation / Answer

a) myst(0) = * b) myst(1) = [*] c) myst(2) = [*]) d) myst(3) = [([*])] e) myst(6) = ([([([*])])]) //here is trace of each call    calling myst(0)     n

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