Write a C++ program whichcontains a class named Time having three datamembers .

Question

Write a C++ program whichcontains a class named Time having three datamembers.

The class musthave

·        Adefault and parameterizedconstructor

·       show() method to display the time in proper formatlike HH:MM:SS on the screen

·       get() method to get time from user

·        OverloadedPlus (+) and Minus (-)operators

·        Adestructor

  

You will overload + and -operator for this class.

In main program make 3objects of the Time class time1,time2 and time3 and call theget() functions for time1 and time2 then performtime3 = tim1+time2 and then you will display time3 using itsshow() function.

Note1: While Adding thetime keep in mind do not just add the hours into hours and minutesinto minutes and seconds in seconds , e.g

10:25:10

+01:45:25

---------------------

11:70: 35

Will not be correct,instead your code should add times like, Note that as number ofminutes have increased 60, hour have been increased.

10:25:10

+01:45:25

-------------------

Explanation / Answer

//Here is the c++program, //don't forget to rateit..
#include<iostream> using namespace std;
class Time{      public:    inthr,min,sec;
     Time(){       hr=min=sec=0;       }       Time(int h,int m,int s)       {       hr=h;       min=m;       sec=s;             }               ~Time()      {       hr=min=sec=0;      }    Timeoperator + ( Time t)    {       int h,m,s;       int sum;              sum = (hr + t.hr)*3600 + (min + t.min)*60 + sec +t.sec;              s = sum %60;       sum = sum/60;       m = sum % 60;       h = sum/60;       return Time(h,m,s);    }    voidget()    {       cout<<" Enter hrs:";       cin>>hr;       cout<<"Enter min:";       cin>>min;       cout<<"Enter sec:";       cin>>sec;      }    Timeoperator - ( Time t)    {       int h,m,s;       int sum1,sum2,sum;              sum1 = (hr)*3600 + (min )*60 + sec ;       sum2 = (t.hr)*3600 + (t.min)*60 + t.sec;              if(sum1>sum2)       sum = sum1-sum2;       else       sum = sum2-sum1;       s = sum %60;       sum = sum/60;       m = sum % 60;       h = sum/60;       return Time(h,m,s);    }    voidshow()    {       cout<<"Time is"<<hr<<":"<<min<<":"<<sec<<endl;      }    };       int main()    {    Time t1;    Time t2;    cout<<"Enterfirst time:";    t1.get();    cout<<"Entersecond time:";    t2.get();    Time t_sum = t1 +t2;    Time t_diff = t1 -t2;    cout<<"Sum ";    t_sum.show();    cout<<"Diff ";    t_diff.show();    system("pause");    }

/* Sample output

Enter first time: Enter hrs:10 Enter min:25 Enter sec:10 Enter second time: Enter hrs:1 Enter min:45 Enter sec:25 Sum Time is 12:10:35 Diff Time is 8:39:45 Press any key to continue . . . */

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