1. What is the output of this code? Ist I50, 70, 11, 13, 1, 9, 29, 31 Ist [1] 3

Question

1. What is the output of this code? Ist I50, 70, 11, 13, 1, 9, 29, 31 Ist [1] 3 del Ist 13 1st [3] = 37 1st [5] = lst [4] print(lst) 150, 3 11. 37, 9, 9, 31 b. 13, 50, 11, 37, 29, 29,31 13, 50, 11, 37, 29, 9, 311 d. Syntax error 2. What is the output of this code? lst = [2, 3, 4, 5, 6] for index in rangelen(Ist)): 1st[index] = index print(lst[index], end=' ') 0 1 234 b. 23 456 d. Syntax error 3. What is the output of this code? tuple 3, 4, 5, 6) for index in range(len(tuple_one): tuple_one[index] -index print(tuple-one(index), end=' ') a. 01 234 23456 Syntax error

Explanation / Answer

# Question 1.
#initial list
lst = [50,70,11,13,1,9,29,31]
#update index 1 element to 3.
lst[1] = 3
# lst = [50,3,11,13,1,9,29,31]
#delete 3rd element from lst. i.e 13.
del lst[3]
# lst = [50,3,11,1,9,29,31]
#update 3rd element in list to 37.
lst[3] = 37
#lst = [50, 3, 11, 37, 9, 29, 31]

#update 5th element with 4th element.
lst[5] = lst[4]

#lst = [50, 3, 11, 37, 9, 9, 31]
# Answer is A

############################
#Qeustion 2

lst = [2,3,4,5,6]
for index in range(len(lst)):
#update each value in list with corresponding index
lst[index] = index
print(lst[index],end=' ')

# output would be A.
# 0 1 2 3 4

#############################
tuple_one = (2,3,4,5,6)
for index in range(len(tuple_one)):
tuple_one[index] = index
  
# Answer D. syntax error.
# tuple object does not support item assignment.
# tuples are immutable, i.e cannot be altered

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