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write the following C PROGRAM In this exercise you will write several functions

ID: 3594424 • Letter: W

Question

write the following C PROGRAM

In this exercise you will write several functions that operate on arrays. The individual

functions are detailed below.

(a) The dot product of two arrays are a = [a1, a2, a3…. an]

and b = [b1, b2, b3…. bn] is

a (dot) b = a1b1 + a2b2 + … + anbn

Write a function that computes the dot product of the two arrays.

int dotProduct(const int *a, int size, const int *b, int size2);

(b) Write a function that takes an integer array and returns the number of integers

that are prime in the array.

int numPrime(const int *a, int size);

(c) Write the following function.

void arrayDifference(const int *a, const int *b, int sizeOfA, int

sizeOfB);

This function dynamically creates an array and fills it with all integers that can

be found in a, but not in b. The values in the returned array should be unique;

that is, there should not be any duplicates. Furthermore, the size of the allocated

arrays should not waste memory.

(d) Write the following function.

void arrayIntersect(const int *a, const int *b, int sizeOfA, int

sizeOfB);

This function dynamically creates an array and fills it with all integers that can

be found in a and b. The values in the returned array should be unique; that is,

there should not be any duplicates. Furthermore, the size of the allocated arrays

should not waste memory.

Program flow pseudocode:

Start

Ask user for size of int arrays A & B (assume that both A and B has the

same size)

Dynamically create arrays A & B with size provided by the user

Prompt the user for entering values into A and B

Print menu

Prompt for menu choice

Run the chosen utility function or on invalid input prompt again

Print result of the chosen utility function and return to menu

Loop until exit

end program

Sample Output:

Enter size of array:

3

Enter values for array A:

2 2 4

Enter values for array B:

4 4 4

Main Menu

A: Find Dot Product

B: Find Number of Prime Integers In Array

C: Array A Difference With B

D: Array Intersection

E: Exit

B

Array A or B?

A

2 prime numbers in array A

...Print main menu again...

D

intersection array is: [4]

...Print main menu again...

C

difference array is: [2]

...Print main menu again...

E

Note: the line ...print main menu again... does not mean to print that literal

phrase, it means to print the menu again and is used here to save space.

Explanation / Answer

#include<stdio.h>
#include<stdlib.h>

int numPrime(int *a, int size){
    int i,count = 0;
    int found;
    int j;

    for(i=0; i<size; i++){
       found = 0;
       for (j=2; j<a[i]; j++){
           if (a[i]%j == 0){
              found = 1;
              break;
           }
       }
       if (found == 0)
          count++;
    }
    return count;
}


int dotProduct(int *a, int m, int *b, int n){

    int prod = 0;
    int i;
    if (m > n){
       for (i = 0; i<n; i++){
         prod = prod + a[i]*b[i];
       }
    }
    if (m < n){
       for (i = 0; i<m; i++){
         prod = prod + a[i]*b[i];
       }
    }
    else {
       for (i = 0; i<m; i++){
         prod = prod + a[i]*b[i];
       }
    }
    return prod;
}

void arrayIntersect(int *a, int *b, int m, int n){

   int *d;
   int i,j;
   int count = 0;

       d = (int *)malloc(sizeof(int)*n);
       for (i = 0; i<m; i++){
          for(j=0; j<n; j++){
             if (a[i] == b[j]){
                d[count] = b[i];
                count++;
                break;
             }
          }
       }
  
   printf("Intersection array is [");
   for (i = 0; i<count; i++){
       printf("%d ",d[i]);
   }
   printf("] ");
}

void arrayDifference(int *a, int *b, int m, int n){
   int *d;
   int i,j;
   int count = 0;
   int found;

   d = (int *)malloc(sizeof(int)*m);
   for (i = 0; i<m; i++){
       found = 0;
       for(j=0; j<n; j++){
           if (a[i] == b[j]){
              found = 1;
              break;
           }
       }
       if (found == 0){
         for (j=0; j<count; j++){
           if (d[j] == a[i]){
               found = 1;
               break;
           }
       
         }
         if (found == 0){
            d[count] = a[i];
            count++;
         }
       }
   }

   printf("Difference array is [");
   for (i = 0; i<count; i++){
       printf("%d ",d[i]);
   }
   printf("] ");

  
}


int main(){
  
   char ch[2];
   char ch1[2];
   int *A;
   int *B;
   int *C;
   int n,i;

     printf("Enter size of array : ");
      scanf("%d",&n);
      A = (int *)malloc(sizeof(int)*n);
      B = (int *)malloc(sizeof(int)*n);

      printf("Enter A: ");
      for (i = 0; i<n; i++){
          scanf("%d",&A[i]);
      }
      printf("Enter B: ");
      for (i = 0; i<n; i++){
          scanf("%d",&B[i]);
      }

   while(1){

      printf("A.Find Dot Product ");
      printf("B.Find Number of Prime Integers In Array ");
      printf("C.Array A Difefrence With B ");
      printf("D.Array Intersection ");
      printf("E.Exit ");

      printf("Enter your choice (A,B,C,D,E):");
      scanf("%s",ch);
      if (ch[0] == 'E')
         break;
      if (ch[0] == 'A'){
         printf("Dot product of A and B is %d ",dotProduct(A,n,B,n));
        
      }
      if (ch[0] == 'B'){
         printf(" Array A or B: ");
         scanf("%s",ch1);
         if (ch1[0] == 'A'){
             printf("%d prime numberes in array %c ",numPrime(A,n), 'A');
         }
         if (ch1[0] == 'B'){
             printf("%d prime numberes in array %c ",numPrime(A,n), 'B');
         }
        
      }
      if (ch[0] == 'C'){
         arrayDifference(A,B,n,n);
        
      }
      if (ch[0] == 'D'){
         arrayIntersect(A,B,n,n);
        
      }
     
   }
  
   return 0;
}