Question Not yet answered Marked out of 1.00 Assume the following code is execut

Question

Question Not yet answered Marked out of 1.00 Assume the following code is executed on the PIPE machine that does forwarding: 0x000: 0x000: 30f65800000000000000 I 0x00a: 30f76000000000000000 | 0x014: 50660000000000000000 I 0x01e: 50770000000000000000 I 0x028: 6176 0x02a: 724600000000000000 0x033: 30f00000000000000000 I 0x03d: 705000000000000000 0x046 : 30f00100000000000000 | less: irmovg $1, %rax 0x050: 00 0x058: 0x058: 0c00000000000000 num1: quad 12 0x060: 0800000000000000 num2: quad 8 -pos 0 irmovq num1 , %rsi irmovq num2, %r01 mrmovq (%rsi), %rsi mrmovq (%rdi), %rdi subq %rdi, %rsi ji less irmovq $0, %rax jmp done Fla question | done: halt .align 8 What instruction is fetched after the 0x02a: 724600000000000000 j less Select one: 0x050: 00 I done: halt 0x03d: 705000000000000000 jmp done C. 0x033: 30f00000000000000000 | irmovq $0, %rax 0x046: 30f00100000000000000 | less: irmovg $1, %rax

Explanation / Answer

Answer: c irmovq $0, %rax

Explanation:

The values in %rsi and %rdi are 0c00.... and 0800.... Respectively

The result for subq %rsi, %rdi will be positive will not update the negative flag

Therefore jl less is not executed, in which PC points to next instruction

So the next instruction that is executed after jl jess is

irmovq $0, %rax.

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