1. (2 pts) Consider classfull addressing and find the network ID and host ID for
ID: 3590437 • Letter: 1
Question
1. (2 pts) Consider classfull addressing and find the network ID and host ID for the following IP addresses: 75.0.0.13 100.2.4.1 220·102.229·10 224.3.2.1 2. (2 pts) Consider classless addressing and find the network address for the following address: IP address: 129.0.161.13 Netmask: 55.255.224.0 3. (2 pts) What is the sub-network address if the destination address is 191.51.22.70 and the subnet mask is 255.255.240.0? (2pts) What is the subnet mask for a class B network that was divided into the biggest number of subnets? 4. 5. (6 pts) A company is assigned the network address 200.0.0.0. The company needs 4 subnets. Design the subnets (i.e., find the subnet mask and for each subnet determine the following: subnet address, 1st and last host addresses, and broadcast address) (6 pts) A company is assigned the network address 189.1.0.0. The company needs 8 subnets. Design the subnets (i.e., find the subnet mask and for each subnet determine the following: subnet address, 1st and last host addresses, and broadcast address) 6.Explanation / Answer
1. Below are the class details:-
a) 175.0.0.13
its a class B address So network ID is 175.0 and host id is 0.13
b) 100.2.4.1
its a class A address so, network id is 100 and host id is 2.4.1
c) 220.102.229.10
Its a class C address so, network id is 220.102.229 and host id is 10
d) 224.3.2.1
Its a class D multicast address, So there is no host id
2. Here we do AND of ip address and mask , so network address is 129.0.160.0
3.Similar to q.2 the subnetwork address is 191.51.16.0
4. Maximum possible subnets of class B are 16382 with 2 hosts per subnets and the mask for it are 255.255.255.252
Class A 1.0.0.1 to 126.255.255.254 Supports 16 million hosts on each of 127 networks. Class B 128.1.0.1 to 191.255.255.254 Supports 65,000 hosts on each of 16,000 networks. Class C 192.0.1.1 to 223.255.254.254 Supports 254 hosts on each of 2 million networks. Class D 224.0.0.0 to 239.255.255.255 Reserved for multicastgroups. Class E 240.0.0.0 to 254.255.255.254 Reserved for future use, or Research and Development Purposes.Related Questions
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