Do only #2: Problems Related to Propagation Delay and Transmission Time 1 Proble
ID: 3588373 • Letter: D
Question
Do only #2:
Problems Related to Propagation Delay and Transmission Time 1 Problem Suppose two hosts A and B are separated by 20,000 kilometers and are connected by a direct link of rate R = 2 Mbps. Suppose the propagation speed over the link is 2.5 × 108 meters/sec I. Calculate the bandwidth delay product, R × dprop 2. Consider sending a file of size 800,000 bits from host A to host B. Suppose the file is sent continuously as one large message. What is the maximum number of bits that will be in the link at any given time? 3. Provide an interpretation of the bandwidth delay product 4. What is the width (in meters) of a bit in the link? Is it longer than a football field? 2 Problem The New Horizon spacecraft that recently flew past Pluto 1 has a high resolution camera LORRI (Long Range Reconnaissance Imager) which has a 1024 pixel by 1024 pixel resolution with each pixel being 12 bits. After applying some compression each image is approximately 2.5 Mb (Megabits). The distance to Pluto is 7.5 billion kilometers and the speed of light is 3 108 meters per second 1. Suppose the data rate of a direct link between New Horizon and an Earth receiver is 1200 bps. What is the time to receive one image? 2. Mars is 225 million kilometers from Earth. The Mars Atmosphere and Volatile EvolutioN (MAVEN)2 is a spacecraft that is currently orbiting Mars. We can achieve a data rate of 1 Mbps between New Horizon and MAVEN as well as between MAVEN and the Earth receiver. Suppose we deploy an intermediate router in MAVEN. If an entire image is put in a packet with an header that is 100 bytes what is the time to receive an image at the Earth receiver? 3. If the image is partitioned into 1000 parts. What is the time to receive an image? 4. If the the data rate between MAVEN and Earth receiver is doubled3 What will be the time to receive an image? https://www.nasa.gov/mission_pages/newhorizons/main/index.html http://www.nasa.gov/mission_pages/maven/main/index.htm.l This is achieved when Mars moves closer to sun so there is more power generated by the solar panels and hence more transmit powerExplanation / Answer
1
1) bandwidth delay product = R * dprop
dprop = Distance / propogation speed
= 20000 * 1000 / 2.5* 108
= 0.08 sec denotes after 0.08sec a bit transferred from sender is received at received end.
bandwidth delay product = 2*106 * 0.08 = 160000 bits
2) Maximum number of bits that can be on the link at any given point = bandwidth delay product
as message size 800,000 bits is greater than 160,000 bits so our answer is 160000bits
3) Bandwidth delay product defines maximum number of bits that can be present in the link at any given point of time.
4) Width of bits in the link = Total Length of transmission line / Maximum number of bits that can fill the link
= 20000 * 1000 / 160000
= 125 metre
Considering football field length of 110 metre. Yes, it is longer than football field.
2
1)
Propogation Time = Distance / Propogation Speed
= 7.5* 109 * 103 / 3 * 108
= 25000 sec
Transmision Time = Message Size / data rate of direct link
= 2.5 * 106 / 1200 = 2083.33 sec
Total time taken = propogation time + transmission time
= 25000 + 2083.33
= 27083.33 secs
2) Total time taken = Time taken (New Horizon to MAVEN) + Time taken(MAVEN to earth)
= (7.275 * 109 * 103 / 3 * 108 )+ (2.5 * 106 + 8*32 )/ 106 + (225*106 * 103 / 3 * 108) + 2.5/1
= 25005 secs
3) No, impact on time taken
4)
Total time taken = Time taken (New Horizon to MAVEN) + Time taken(MAVEN to earth)
= (7.275 * 109 * 103 / 3 * 108 )+ (2.5 * 106 + 8*32 )/ 106 + (225*106 * 103 / 3 * 108) + 2.5/2
= 25003.75 secs
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