AT&T; LTE 9:49 AM please answer all parts and show all work You are the head of

Question

AT&T; LTE 9:49 AM please answer all parts and show all work You are the head of a design team. Two colleagues have submitted their Verilog code designed to implement the circuit in Fig.1.Code A is an attempt at a behavioral implementation, and Code B is an attempt at a structural implementation. Your job is to determine which of the two codes should be used and justify your decision. Note: Your answer should be based on analysis of the code. Your answer should not be "Behavioral is better than structural, so I pick Code A." Code A //2x4 Decoder module Decoder24 output wire W, output wire X, output wire Y, output wire Z input wire [1:0] S, Code B //2x4 Decoder module Decoder24 output wire W, output wire X, output wire Y, output wire Z, input wire SO input wire S1, always@(*) case(S) assign w =-SI & ~SO; assign XSI & SO; assign Y = Si & ~S0: assign Z-S1 & SO endmodule 0: w=1; 2: Y-1 3: Z-1: default: w=1; endcase endmodule

Explanation / Answer

Solution:

As code A has defined outputs as wire so,

We cannot assign some values to these variables w,x,y,z in the always block.

So, If we go with code A we will error.

Hence, We go for code B

Code B

//2x4 Decoder

module Decoder24 (

output wire W,

output wire X,

output wire Y,

output wire Z,

input wire S0,

input wire S1,

);

assign W= ~S1 & ~S0;

assign X= ~S1 & S0;

assign Y= S1 & ~S0;

assign Z= S1 & S0;

endmodule

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