What is the output of the following c++ program? double add ( double x, double y

Question

What is the output of the following c++ program?

double add ( double x, double y) (return x+y;)

double sub (doublex, double y) (return x-y;)

double mul (double x, double y) (return x * y;)

double div (double x, double y) (return x/y;)

double f(double(*p) (double, double), int n)

{

double u = 5.0, v=-2.0;

return n * p(u,v);

}

int main( )

{

cout << f(add, 2) <<endl;

cout << f(sub,3) <<endl;

cout << f(mul,1) <<endl;

cout << f(div, -5) << endl;

return 0;

}

Help explain output step by step please

Explanation / Answer

Output:

6
21
-10
12.5

//f(add, 2) => p(u,v) => 5.0+(-2.0) = 3.0
//[p(u,v) * n] = 3.0 * 2 = 6

//f(sub, 3) => p(u,v) => 5.0-(-2.0) = 7.0
//[p(u,v) * n] = 7.0 * 3 = 21

//f(mul, 1) => p(u,v) => 5.0*(-2.0) = -10.0
//[p(u,v) * n] = -10.0 * 1 = -10

//f(div, -5) => p(u,v) => 5.0/(-2.0) = -2.5
//[p(u,v) * n] = -2.5 * -5 = 12.5

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