5. In the ADO0804, INTR is an tion in the ADC0804? For an ADOos04 chip, find the

Question

5. In the ADO0804, INTR is an tion in the ADC0804? For an ADOos04 chip, find the step size for each ofthe following v (a) vref 2 128 v (b) Vref 2 IV (c) vref2 -1.9 v 7. In the ADC0804, what should be the Vref2 value for a step size of 20 mws 8. In the ADC0804, what should be the Vref2 value for a step size of mv 9. In the ADC0804, what is the role of pins vin and vin-? 10. With a step size of 19.53 mV what is the analog input voltage if al are I? DWith vref2-064 V. find the vin for the following outputs. (a) D7 D0 11111111 (b) D7-D0" 10011001 (c)D? Do 1101100 12, True or false. ADO0804 is an 8-bit ADC. 13. Which of the following ADCsizes provide the best resolution? (a) 8-bit (b) 10-bit (c) 12-bit (d) 16-bit 6e) They are all the same. 14. In Question 13, which provides the smallest step size 15. Calculate the step size for the following ADCs, ref is 5 V (a) 8-bit (b) 10-bit (c) 12-bit edy 16-bit 16, True or false. ADC0808/0809 isan 8-bit ADC 17. Indicate the direction (in, out) for cach of the following ADO08080809 pins. (a) SC (b) EOC (c) A, B C (d) ALE (c) OE (g) D0 18. Explain the role of the ALEpin in the ADCOsosos09 and show how to select channel 5 analog input. 19. In the ADC08080809, assume Vref Gnd Give the V,ef voltage value if we want the following step sizes: (a) 20 mV (b) 5 mV (c) 10 mv (d) 15 mV (e) 2 mV (f 25 mV 20. In the ADC08080809, assume vrefe--Gnd Find the step size for the fol lowing values of Vreft (a) 1.28 V (b) IV (c) 0.64 V 21. True or false. ADCO848 is an 8-bit ADC. Give the status of Cs and WR in order to start conversion for the ADcosas. 21, Give the status of cs and WR in order to get data from the ADCOss. 24. In the ADC0848 what happens to the convened analog data? How do we know that the ADC is ready to provide us the data? 25, In the ADCO848 what happens to the old data if we start conversion agan before we pick up the last data? 26. In the ADC0848 INTR is an (input, output) signal. What is its func- tion in the ADC0848? 27. For an ADC0848 chip, find the step size for each of the following Vref (a) V 1.28 V (b) Vref i V (c) V 1.9 V

Explanation / Answer

6.

a. Vref/2 = 1.28v,

so,input voltage span= 0 - 2.56v

Step size (mV) = 2.56/255 = 10.04

b. Vref/2= 1v

so,input voltage span= 0 - 2v

Step size (mV) = 2/255 = 7.84

c. Vref/2= 1.9v

so,input voltage span= 0 - 3.8v

Step size (mV) = 3.8/255 = 14.90

11. Solution:

Concept: Vin = Resolution * Binary-to-Decimal

Resolutin = Vref/255

Given, Vref/2=0.64V, Vref= 0.64*2= 1.28V

Step size = 1.28/255= 5mV

Ans. a. Since the step size is 5mV and all input are high, we get 255*5mV= 1.275V

Ans.b. 10011001 = 153 in Decimal

so, 153*5 mV= 0.765V

Ans. c. 1101100= 108 in Decimal

so, 108*5 mV= 0.540 V

22. Answer

CS input and WR input remain low, the ADC will remain in a reset state. Conversion will start from 1 to 8 clock periods after at least one of these inputs makes a low-to-high transition

54. Answer:

concept: Iout = resolution* Binary to Decimal

Resolution = Iref/256

Given, Iref= 2mA

a. 10011001 , Decimal=153

Iout= 2mA(153/256)= 1.195mA

b.11001100 , Decimal= 204

Iout= 2mA(204/256)= 1.59mA

c.11101110 = 238

Iout= 2mA(238/256)= 1.85mA

d. 00100010 , Decimal- 34

Iout= 2mA(34/256)= 0.26mA

e. 00001001, Decimal- 9

Iout= 2mA(9/256)= 0.07mA

f. 10001000, Decimal- 136

Iout = 2mA(136/256)= 1.06mA

Note: Solutions provided - Questions: 6,11,22,54

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