Write a function named countMultiples, which takes in a given integer n, counts

Question

Write a function named countMultiples, which takes in a given integer n, counts how many non-zero numbers in the input are a multiple of n, and returns this count. The function reads the numbers entered user. The user enters a sequence whole numbers ending with zero. Different users may enter different number of numbers. Write a driver program which repeatedly prompts the user to enter a non-zero whole number reads the number, calls countMultiples, and prints the result until the user decides to quit the program. No comments needed.

Explanation / Answer

Both of the solutions are working as per complete requirements. Do see it. :)

The answer for the 1st part is:

C-Program :

#include<stdio.h>
#define SIZE 100

int countMultiples(int n)
{
int i=0, enteredno;

int count=0;

int no[SIZE] ={0};

printf(" Good. Now enter numbers, press 0 to terminate in between. ");

do
{
scanf("%d", &enteredno);

if(enteredno != 0)
no[i++] = enteredno;

else
break;
}
while(i<SIZE);

for(i=0; no[i]!=NULL; i++)
{
if(no[i] % n == 0)
count++;
}

return count;
}

The answer for the 2nd part is: (This is the complete code along with above mentioned code)

C-Program:

#include<stdio.h>
#define SIZE 100

int countMultiples(int n)
{
int i=0, enteredno;

int count=0;

int no[SIZE] ={0};

printf(" Good. Now enter numbers, press 0 to terminate in between. ");

do
{
scanf("%d", &enteredno);

if(enteredno != 0)
no[i++] = enteredno;

else
break;
}
while(i<SIZE);

for(i=0; no[i]!=NULL; i++)
{
if(no[i] % n == 0)
count++;
}

return count;
}

void main()
{
int n, result;

char choice;

do
{

printf("Enter a whole - number: ");
scanf("%d", &n);
result = countMultiples(n);
printf(" Required count is : %d", result);

printf(" Do you want to continue? (y/n) Enter your choice: ");
scanf(" %c",&choice);

}

while(choice=='Y' || choice=='y');
}

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