Write a PHP function increase () that has two parameters, the first by-reference

Question

Write a PHP function increase () that has two parameters, the first by-reference. and the second by-value. It adds the value of the second on to the first. For example, $u = 2; increase ($u, 3); echo $u; outputs 5. Note that there is no return statement. Answer (My solution has one line in the body of the function.) Write a PHP class MyClass that has one public property. $x. which is expected to be a number and is initialized when an instance is created. This class has one instance method, foo (). which is passed a number and returns the sum of that number and the value of property $x (Do not check that values arc of the proper type.) For example. $cl = new MyClass (2); echo $cl rightarrow foo(3); outputs 5. (My solution has 6 lines, not counting blank lines and lines containing only brackets.)

Explanation / Answer

Answer

(7)

<?php

    

     $originalvalue = 20;

     //&$u reference variable

     //function defination

     function increase(&$u,$num){

          //sum of two values

          $sumofvalue = $u + $num;

          echo "sum of two values = $sumofvalue";

          }

     //method call

     increase($originalvalue,3);

?>

Answer

(8)

<?php

//class MyClass declaration

class MyClass{

     //$x declaration

     var $x;

     //foo method

     function foo($num){

          // sum of x and num values

          $sum = $x + $num;

          //return sum

          return $sum;

     }

}

//object creation

$c1 = new MyClass(2);

//method call with object

echo $c1->foo(3);

?>

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