Write a bash script that does the following: 1 Takes as its single parameter the

Question

Write a bash script that does the following: 1 Takes as its single parameter the path to, and name of a file. 2 Inside the script, use the cat command and a for line in… construct to display the lines in the specified file, preceding each line with the line number and a colon (“:”). Put the whole line inside single quotes. 3. Do not use the cat flag that would do this trivially; rather, keep track of which line you are on inside the for loop, and have your code generate and display the line numbers.

Explanation / Answer

Run it as ./<script-name> <file-path>

#!/bin/bash
COUNTER=0
FILEPATH=$1   #takes filepath from input provided

cat $FILEPATH |     #redirecting output to next while loop
while read line; do    #reading line by line from above output, i.e output of cat <file-name>
   echo $COUNTER':' $line   #echoing required matter
   let COUNTER=COUNTER+1 #incrementing line counter
done

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