using Java. 13.6 Program: Division By Zero This program will test exception hand

Question

using Java.

13.6 Program: Division By Zero

This program will test exception handling during division.

The user will enter 2 numbers and attempt to divide (in a try block) the 1st number by the 2nd number.

The program will provide for 2 different catch statements:

Division by zero - denominator is zero - program will throw an ArithmeticException object

Division results in a negative number - program will throw an Exception object

The user should be prompted with

For input of 7 and 0 the output should be

For input of 7 and 2 the output should be

For input of 7 and -2 the output should be

L

Lab Submission

13.6.1: Program: Division By Zero

Instructions

Deliverables

DivideByZero.java

We will expect the above file(s) to be submitted

Compile command

javac DivideByZero.java -Xlint:all

We will use this command to compile your code

Submit your files below by dragging and dropping into the area or choosing a file on your hard drive.

DivideByZero.java

Drag files to left, or choose file...

SUBMIT FOR GRADING

Instructions

Deliverables

DivideByZero.java

We will expect the above file(s) to be submitted

Compile command

javac DivideByZero.java -Xlint:all

We will use this command to compile your code

Submit your files below by dragging and dropping into the area or choosing a file on your hard drive.

DivideByZero.java

Drag files to left, or choose file...

SUBMIT FOR GRADING

Explanation / Answer

Hi, Please find my implementation.

Please let me know in case of any issue.

import java.util.Scanner;

public class DivideByZero {

   public static void main(String[] args) {

       Scanner sc = new Scanner(System.in);

       try{

           System.out.println("Enter two numbers: ");

           int num1 = sc.nextInt();

           int num2 = sc.nextInt();

           if(num2 == 0)

               throw new ArithmeticException("Exception: Division by zero");

           double div = (double)num1/(double)num2;

           if(div < 0)

               throw new Exception("Exception: Division is negative");

           System.out.println(num1+"/"+num2+" = "+div);

       }catch(ArithmeticException e){

           System.out.println(e.getMessage());

       }catch(Exception e){

           System.out.println(e.getMessage());

       }

   }

}

/*

Sample run:

Enter two numbers:

4

5

4/5 = 0.8

Enter two numbers:

4

0

Exception: Division by zero

Enter two numbers:

9

-4

Exception: Division is negative

*/

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