What is the output of the following program segment? in C++ double temp[ 5]; for

Question

What is the output of the following program segment? in C++

double temp[ 5];

for ( int i = 0; i < 5; i++)

temp[ i] = pow( i, 2.0) + 2;

for ( int i = 0; i < 5; i++)

cout << temp[ i] << " "; cout << endl;

temp[ 0] = pow( temp[ 1], 3);

temp[ 1] = temp[ 4] - temp[ 2];

temp[ 2] = temp[ 0] - 5;

for ( int i = 0; i < 5; i++) cout << temp[ i] << " "; cout << endl;

I have two more if anybody can help....

What is stored in list after the following C++ code executes?

int list[ 10];

for ( int i = 0; i < 5; i++)

{ list[ i] = i * i - 5;

if ( i % 3 == 0) list[ i] = list[ i] + i;

else list[ i] = list[ i] - i; }

and this one.

What is stored in list after the following C++ code executes?

int list[ 10];

list[ 0] = 2;

list[ 1] = 3;

for ( int i = 2; i < 10; i++)

{ list[ i] = list[ i - 1] + list[ i - 2];

if ( i > 7) list[ i] = 2 * list[ i] - list[ i - 2]; }

Explanation / Answer

#include<iostream>
#include<math.h>
using namespace std;
int main()
{
   double temp[ 5];

   for ( int i = 0; i < 5; i++)
   temp[ i] = pow( i, 2.0) + 2; //square i=0,1,2,3,4 and add 2 to it
  
   /*so
   * temp[0]=2
   * temp[1]=3
   * temp[2]=6
   * temp[3]=11
   * temp[4]=18
   */
   for ( int i = 0; i < 5; i++)
   cout << temp[ i] << " "; cout << endl; //Prints the values of temp[i]

   temp[ 0] = pow( temp[1], 3); //temp[0]=pow(3,3) i.e cube of 3 =3*3*3=27

   temp[ 1] = temp[ 4] - temp[ 2]; //temp[1]=18-6=12

   temp[ 2] = temp[ 0] - 5;//temp[2]=27-5=22

   /*so new values
   * temp[0]=27
   * temp[1]=12
   * temp[2]=22
   * temp[3]=11
   * temp[4]=18
   */
   for ( int i = 0; i < 5; i++)
   cout << temp[ i] << " "; //Prints the values of new temp[i]
  

   cout << endl;
}

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