Having trouble with writing the following 3 function definitions in C++. Any hel

Question

Having trouble with writing the following 3 function definitions in C++. Any help with any of them would be very appreciated.

1) Write a function called Reverse that takes in two parameters: an integer array the size of the array. This function should reverse the order of the array's contents. No returned value.

2) Write a function called HowMany that takes in three parameters:

This function should count the number of occurences of the given value in the array (i.e. how many times this value appears), and then return the count.

3) Write a function called SumEvens that takes in three parameters:

This function should compute and return the sum of the first N even values in the array. (If there are fewer than N even numbers, then you'll just add them all (i.e. all of the even numbers)).

Thank you. I just need help with the definitions. If you can help with any of them I would appreciate it.

Explanation / Answer

#include<iostream>
void Reverse(int a[],int size);
int HowMany(int a[],int size,int num);
int SumEvens(int a[],int size,int N);
int main()
{
   int a[100];
   int n;
   cout<<"Enter array size ";
   cin>>n;
   cout<<"Enter array elements ";
   for(int i=0;i<n;i++)
   {
       cin>>a[i];
   }
   cout<<"Reverse of array ";
   Reverse(a,n);
   for(int i=0;i<n;i++)
   {
       cout<<a[i]<<" ";
   }
   cout<<"Enter element to find ";
   int num;
   cin>>num;
   int count = HowMany(a,n,num);
   cout<<"Number of occurences is :"<<count<<" ";
  
   cout<<"Enter first N even value ";
   int even;
   cin>>even;
   int sum = SumEvens(a,n,even);
   cout<<"Sum of First N even numbers is :"<<sum<<" ";

}
void Reverse(int a[],int size)
{
   int temp;
   for(int i=0;i<size/2;i++)
   {  
       temp = a[i];
       a[i] = a[size-i-1];
       a[size-i-1]=temp;
   }
}
int HowMany(int a[],int size,int num)
{
   int count=0;
   for(int i=0;i<size;i++)
   {
       if(a[i]==num)
           count++;
   }
   return count;
}
int SumEvens(int a[],int size,int N)

{

   int sum=0,count=0;
   for(int i=0;i<size;i++)
   {
       if(a[i]%2==0)
       {
           if(count<N)
           {
               sum = sum + a[i];
               count++;
           }
       }
   }
   return sum;
}

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