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Write a program that reads in an array of type int. You may assume that there ar

ID: 3555725 • Letter: W

Question

Write a program that reads in an array of type int. You may assume that there are fewer
than 50 entries in the array. Your program determines how many entries are used. The
output is to be a two-column list. The first column is a list of the distinct array elements;
the second column is the count of the number of occurrences of each element. The list
should be sorted on entries in the first column, largest to smallest.

For the array values:

-12 3 -12 4 1 1 -12 1 -1 1 2 3 4 2 3 -12

the output should be

N Count
4 2
3 3
2 2
1 4
-1 1
-12 4

Explanation / Answer

#include <iostream>
#include <stdlib.h>
using namespace std;

void fillArray(int a[], int size, int& numberUsed);
void showFrequency (int a[], int SIZE);
void CheckDuplicate( int num, int arry[], int SIZE, int index);


int main( )
{
int sampleArray[50]={-12, 3, -12, 4, 1, 1, -12, 1, -1, 1, 2, 3, 4, 2, 3, -12};
int numberUsed; //the index

fillArray (sampleArray, 50 , numberUsed);


showFrequency (sampleArray, numberUsed);
return 0;
}



void fillArray(int a[], int SIZE, int& numberUsed)
{
int nums=16;
cout << "Enter up to " << SIZE << " whole numbers. ";
cout << "How many numbers do you want to enter? ";
cin >> nums;

for(int index; index < nums; ++index)
{
//cin >> a[index];
}
numberUsed=nums;
}

void showFrequency (int a[], int SIZE)
{
int prev = a[0], count = 0;
cout << " Number count ";
//cout << a[0] << " ";
for (int i=0; i< SIZE; i++)
{
CheckDuplicate(a[i], a, SIZE, i);
}
}

void CheckDuplicate( int num, int arry[], int SIZE, int index)
{
bool duplicate=false;
bool hasNumAppeard=false;
int counter=0;
static int *temp = new int[SIZE];
temp[index]=num;

for(int x=0; x < index; ++x)
{
if(temp[x]==num){
hasNumAppeard=true;
}
}

for(int x=0; x < SIZE; ++x)
{
if(arry[x]==num){
duplicate = true;
++counter;
}
}
if(duplicate==true && hasNumAppeard==false){
cout<<num<<" "<<counter<<endl;
}
}

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