Write a program for the following: Assume that your computer has the very limite

Question

Write a program for the following:

Assume that your computer has the very limited capability of being able to read and write

only single-integer digits and to add two integers consisting of one decimal digit each. Write a

program that can read two integers up to 30 digits each, add these integers together, and

display the result. Test your program using pairs of numbers of varying lengths.

Hint: Store the two numbers in two int arrays of size 30, one digit per array element. If the

number is less than 30 digits in length, enter enough leading zeros (to the left of the number)

to make the number 30 digits long.

You will need a loop to add the digits in corresponding array elements. Don

Explanation / Answer

#include<iostream>

#include<string>

#include<fstream>

#include<conio.h>

using namespace std;

void AddTwoArray(int [],int [],int []);

int main()

{

char FirstNumberString[30], SecondNumberString[30];

int FirNum[30], SecNum[30];

int Sum[31];

ifstream myReadFile;

myReadFile.open("input.txt");

cout << "Enter two numbers :" << endl;

myReadFile >> FirstNumberString >> SecondNumberString;

myReadFile.close();

//convert string to int

int i;

//First Number

for (i=0; i<30-strlen(FirstNumberString); i++)

FirNum[i]=0;

for (int j=0; i<30; i++, j++)

{

FirNum[i]=FirstNumberString[j]-48;

}

//for second number

for(i=0;i<30-strlen(SecondNumberString);i++)

SecNum[i]=0;

for(int j=0;i<30;i++,j++)

{

SecNum[i]=SecondNumberString[j]-48;

}

AddTwoArray(FirNum, SecNum, Sum);

//addition print

ofstream output;

output.open("input.txt");

cout << " Addition of both numbers is :";

for (int i=0; i<31; i++)

{

if (Sum[i]==0)

continue;

output << Sum[i];

}

output.close();

getch();

}

void AddTwoArray(int F[], int S[], int sum[])

{

int carry =0;

for (int i=29; i>=0; i--)

{

if (S[i]+F[i]+carry>9)

{

sum[i+1]=(S[i]+F[i])%10;

carry=1;

}

else

{

sum[i+1]=(S[i]+F[i]);

carry=0;

}

}

sum[0]=carry;

}

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