How to run my Python 2.7 code on Python 3.0? here is my Python 2.7 code: 1 2 3 4

Question

How to run my Python 2.7 code on Python 3.0?

here is my Python 2.7 code:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 def game(army1, army2):    prisoner1=""     prisoner2=""     print "Player 1:",army1," ",prisoner1     print "Player 2:",army2," ",prisoner2     print " "     while(len(army1) and len(army2)):         if(army1[0]=='H' and army2[0]=='T'):             prisoner1="TH"+prisoner2+prisoner1             prisoner2=""             army1=army1[1:]             army2=army2[1:]         elif (army1[0]=='T' and army2[0]=='H'):             prisoner2="TH"+prisoner1+prisoner2             prisoner1=""             army1=army1[1:]             army2=army2[1:]         else:             prisoner1+=army1[0]             prisoner2+=army2[0]             army1=army1[1:]             army2=army2[1:]             if(len(army1)):                 prisoner1+=army1[0]                 army1=army1[1:]             if(len(army2)):                 prisoner2+=army2[0]                 army2=army2[1:]         print "Player 1:",army1," ",prisoner1         print "Player 2:",army2," ",prisoner2         print " "     if(len(army1) and len(army2)==0):         print "Player 1 wins."     elif(len(army1)==0 and len(army2)):         print "Player 2 wins."     else:         if(prisoner1.count('H')>prisoner2.count('H')):             print "Player 1 wins."         elif(prisoner1.count('H')<prisoner2.count('H')):             print "Player 2 wins."         else:             print "Tie." def createRandom(army):     opp=""     for i in range(len(army)):         opp+="HT"[randint(0,1)]     return opp total=input("Enter number of games to be played :") for i in range(total):     print " Game :",i+1     seq=raw_input("Enter army sequence :")     # Change below line to :     # game(seq,createRandom(seq))     # if you want to randomly generate opposite army     game(seq[:5],seq[5:])

Explanation / Answer

New sourcecode: https://www.dropbox.com/s/17a7jaszbvbgvyi/code_python3.py

Changes made:

1.line 52: convert scanned string to an int

2.line 54: python 3 has no print statement only a print function

3.line 55: python 3 has no raw_input() instead it has input()

4.line 2 : Identation

5.line 4,5,6: print statement

6.line 30,31,32,34,36,39,41,43: print statement

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