What does the following program print out? There are no actual number, so in wha

ID: 3540172 • Letter: W

Question

What does the following program print out? There are no actual number, so in what is being computed?

int bry[200], size sumNbr, count;

int *p;

...assume more code here to fill array with values. Number of values in array is ' size '

sumNbr = SumIt(bry, size, average); //program you wrote earlier on this test

p = bry; count = size;

for ( i = 0; i < size; i++)

{ if ( *p < average)

{ count = count -1;

p = p +1;

}

cout << " count: " << count << endl;

What is the statement ' int *p ' defining? Be specific.

What does the ' *p ' mean in the statement if ( *p < average )? ( Less than average is not the answer)

What is happening in the statement 'p = p + 1' ? Be specific.

Given the following sorted data, show the values of low, high, and mid to find the value 16. Show all work.

0 1 2 3 4 5 6 7 8 9 <--- subscripts to the array

1 2 7 8 12 13 16 19 21 24 <--- values in the array

What happens to low and high values if we looked up the value of 15 in the above list?

this is the program which will take a list of numbers and find the mid number.

What is the statement ' int *p ' defining? Be specific.

it is the initializing or defining of the pointer of p. which is *p

What does the ' *p ' mean in the statement if ( *p < average )?

this instruction will check if the pointer of p is less than the average integer

it will be true if the array will be having less than the half digits in memory....but i don't seen any definition of integer "average"...!

What is happening in the statement 'p = p + 1' ? Be specific.

this will move the pointer of p to next level or to next number.

Given the following sorted data, show the values of low, high, and mid to find the value 16. Show all work.

0 1 2 3 4 5 6 7 8 9 <--- subscripts to the array

1 2 7 8 12 13 16 19 21 24 <--- values in the array

low=>> 1 2 7 8

mid=>> 16

high=>> 19 21 24

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