Problem: Given five integers that make a series determine the next five numbers

ID: 3538220 • Letter: P

Question

Problem: Given five integers that make a series determine the next five numbers in the series. There are only two possible series and they are defined as follows:

1. Addition %u2013 Each number in the series is separated by the same amount.
2. Multiplication %u2013 Each number in the series is a product of the previous number in the series and a constant integer value.

Example Execution #1:

Example Execution #2:

Example Execution #3:

Example Execution #4:

Example Execution #5:

Enter the first five number of the series: 1 2 3 4 5
The next number five numbers in the series are: 6 7 8 9 10

The use of any selection constructs (if/else, switch, conditional expressions), logical and relational operators (&&, ||, !, <, <=, ==, >=, >), and Boolean variables are prohibited on this assignment. Only user defined functions can be can be used.

I need the code and the logic. Will Award full points who gives the correct code.

Explanation / Answer

#include <stdio.h>

void nextFiveNumber(){

long long int prev;

long long int next;

long long int first;

printf("Enter the first five number of the series: ");

scanf("%lld",&prev);

first = prev;

scanf("%lld",&next);

long long int diff = next - prev;

long long int temp = diff;

long long int factor = next/prev;

prev = next;

scanf("%lld",&next);

temp -= next-prev;

prev = next;

scanf("%lld",&next);

prev = next;

scanf("%lld",&next);

prev = next;

int c = -temp/(first*(factor-1)*(factor-1));

printf("The next number five numbers in the series are: ");