A p l a y e r ro lls t w o d i ce . Eac h d ie h a s s i x f ac e s . T h e s e

Question

A player rolls two dice. Each die has six faces. These faces contain 1, 2, 3, 4, 5, and 6 spots. After the dice have come to rest, the sum of the spots on the two upward faces is calculated.

%u2022   If the sum is 7 or 11 on the first throw, the player wins.

%u2022   If the sum is 2, 3, or 12 on the first throw (called %u201Ccraps%u201D), the player loses (i.e. the %u201Chouse%u201D wins).

%u2022   If the sum is 4, 5, 6, 8, 9, or 10 on the first throw, then the sum becomes the player's %u201Cpoint.%u201D

o To win, you must continue rolling the dice until you %u201Cmake your point.%u201D The player loses by rolling a 7 before making the point.

Write a program to simulate a game of craps, resulting in a win or loss. Make sure your program displays appropriate messages so that the user can follow each step of the game.

Run the game multiple times to estimate the probability that the player wins. For example, if the player wins

490 out of 1000 games, then the estimated probability of winning is 490/1000 = 0.49. Run the game at least

5000 times.

Explanation / Answer

function main

%play 5000 times

wins=0;

for i=1:5000

wins = wins + game();

end

prob = wins/5000;

fprintf('Probability of winning is : %f ',prob);

function win=game()

roll1=floor((rand()*6)+1);

roll2=floor((rand()*6)+1);

point=0;

win=0;

sum=roll1+roll2;

if sum==7 || sum==11

win=1;

elseif sum==2 || sum==3 || sum==12

win=0;

else

point=sum;

while(true)

roll1=floor((rand()*6)+1);

roll2=floor((rand()*6)+1);

sum=roll1+roll2;

if sum == point

win=1;

break;

elseif sum== 7

win=0;

break;

end

end

end

end

end

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