Abdullah 23443212 Khaled 33433234 Mohammed 44544332 Notice you have no indicatio

Question

Abdullah
23443212

Khaled
33433234

Mohammed
44544332

Notice you have no indication of how many names and numbers in the file info.txt

then will save all names on a file call it names.txt and all numbers on another file called numbers.txt

Names must be encrypted before saved on the names.txt file

encryption should be as follow:

Each character should be shifted twice the position of its location in the world +1

so for example if the word is: 'ali' it will be encrypted to 'bon' because:

'a' will be 'b' since its at zero location and twice zero +1 is 'b'

'l' will be 'o' since it is at location 1 and twice that location +1 is 3 so 'o'

and so on.

Explanation / Answer

#include<iostream.h>

#include<fstream.h>

struct info

{

char name[50];

int num;

};

void main()

{

fstream file,file1,file2;

file.open("info.txt");

file1.open("name.txt");

file2.open("number.txt");

info a;

char n[50];

int i,j;

while(file!=eof)

{

a=file.read((*ch)&a,sizeof(a));

for(i=0;a.name[i]!='';i++)

{

j=i+1;

name[i]=name[i]+j;

}

file1.write((*ch)&a.name,sizeof(a.name));

file2.write((*ch)&a.num,sizeof(a.num));

}

cout<<"name file contain ";

while(file1!=eof)

{

a.name=file1.read((*ch)&a.name,sizeof(a.name));

cout<<a.name<<" ";

}

cout<<"number file contain ";

while(file2!=eof)

{

a.num=file2.read((*ch)&a.num,sizeof(a.num));

cout<<a.num<<" ";

}

file.close();

file1.close();

file2.close();

}

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