It needs to be in the form of a table. IP is below 172.14.103.0/22 Size of subne

Question

It needs to be in the form of a table. IP is below

172.14.103.0/22

Size of subnet 1 - 180

Size of subnet 2 - 50

Size of subnet 3 - 2

The table should have the following headings

Subnet #, Prefix length, subnet mask, # required hosts, max # of hosts, network address, first address , last address, and broadcast address.

For the purpose of not cheating this is NOT the exact problem that has been given to me. I just need some help figuring it out. I am 100% stuck. So if someone knows how to do this please let me know the detailed stepso n how to do this. Come on Chegg, remind me why I pay for this homework help description!!!

Please help me out! :)

Explanation / Answer

The original rules for subnetting in RFC 950 stressed the significance of reserving the subnets whose addresses were constructed of all 0s and all 1s. Depending on the size of the mask being used, this could translate directly into a substantial number of addresses being wasted. Consider a mask of 255.255.255.192 in a Class C network. That size of network has only a mathematically possible 256 host addresses. The subnet mask we've selected would yield four possible subnets, each with 64 mathematically possible host addresses. Reserving subnets 0 and 3 (as per Table 3-4) immediately translates into the loss of 128 of the host addresses. Pragmatically, wasting 128 addresses is better than wasting 384, as you would do if you acquired just two Class C networks and didn't bother subnetting. However, the fact remains that the classical rules are not perfectly efficient. Host Addresses A much more subtle form of loss is found in the host addresses themselves. Again, the all-0s and all-1s addresses are reserved, but this time there's a pair within each subnet. Thus, for each subnet formed, two host addresses can't be used. To continue expanding on the example from the preceding section, the all-0s and all-1s addresses in subnets 1 and 2 are as shown in Table 3-13. Table 3-13. Subnetting with a 6-Bit Mask in a 16-Bit Network Subnet Number Binary Value of the Last Octet All 0s Subnet 1 01-000000 192.169.125.64 Subnet 1 01-111111 192.169.125.127 Subnet 2 10-000000 192.169.125.128 Subnet 2 10-111111 192.169.125.191 Table 3-13 demonstrates that, in addition to losing all of Subnets 0 and 3 (the all-0s and all-1s subnet addresses), you lose four more addresses. That brings the total of unusable addresses to 132 out of the original 255

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.