Given the network 172.16.0.0/16, subnet the network into minimum size subnets ca

Question

Given the network 172.16.0.0/16, subnet the network into minimum size subnets cable of

providing addresses to at least 4096 hosts.

a. Using slash notation, what is the network address of the first network?

b. What is the first usable host address in the first network?

c. What is the last usable host address in the first network?

d. What is the broadcast address in the first network?

e. What is the network address of the second network in the subnet?

f. What is the network address of the third network in the subnet?

g. How many subnets can you create from the original network?

Explanation / Answer

Since at least 4096 host are required we can only create 8 subnetworks of the network 172.16.0.0/16

Ans a.- network address of the first network= 172.16.0.0/19

Ans b.- first usable host address in the first network= 172.16.0.1/19

Ans c. last usable host address in the first network= 172.16.31.224/19

Ans d. broadcast address in the first network= 172.16.31.255/19

Ans e:- network address of the second network =172.16.32.0/19

Ans f:- network address of the third network=172.16.64.0/19

Ans g:- 8 subnetworks can be created for the given scenario.

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